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RE: Breeding Honduran Morphs Question

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Posted by: DMong at Sun Sep 19 15:48:02 2010  [ Report Abuse ] [ Email Message ] [ Show All Posts by DMong ]  
   

You would have been far better off posting this on the "milksnake" forum where it would have gotten a very fast reply. But Honduran (or any colubrid) genetics is FAR different that many of the python/boa genetics. All colubrid mutations are recessive, as opposed to many of the dominant/co-dom traits in the other's.

If you bred a straight-up albino that is carrying no other heterozygous recessive traits to a straight-up ghost(which is a homozygous(visually showing) form of hypo x anery, you will get ALL normals that are triple het for all three traits unless these snakes are also carriers of the same "like" recessive genes. Now when you breed THOSE sibs to each other, or back to a parent, THAT is when you will start getting visual morphs of whatever type of trait they might have genotypically.

Your male albino to a female hypo would produce all normal double hets for amel and hypo(hybino). And your albino(amel) x anerythristic would also produce ALL normal offspring that are double het for anery and amel(snow).

Keep in mind, many Hondos on the market now have lots of recessive traits that are "bi-products" of mutiple morph breedings, so if any of these are actually het for the same things, they can and WILL produce certain morphs, but unless the two parents ARE INDEED het for traits you may, or may not be aware of, you will get ALL normals het for every single trait the morph parents display(and even possibly don't display), this just all depends on many things as to the specific outcomes.


~Doug
-----
"a snake in the grass is a GOOD thing"

my website -serpentinespecialties.webs.com


   

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