>I originally thought that by crossing an albino and an anery would provide actual snows. Was I right about that, or will it produce normal looking het for both?

This mating will produce normal looking babies that are heterozygous for both albino and anerythristic.

>Then breeding a pair that is het for both will provide snows? I'm new to this type of thing, so simple language please

Breeding a pair that are heterozygous for both will (statistically) produce 1/16 snows. The rest will be normals, albinos, and anerythristics.

>If the second scenario is true, what happens if the original albino from 1 of the dh offspring is kahl line, and the albino from the 2nd dh offspring is a sharp? Since I've read that combing kakl sharp provide normal looking het for both strains of albino, but no actual albino, what will the dh snow x dh snow babies end up being?

This is a cross that you do not want to do. Statistically, a quarter of the babies will be anerythristic and the rest will look normal. Any of the babies could be heterozygous for Kahl albino or Sharp albino or both. Any of the normal babies could also be heterozygous for anerythristic.

The problem here is that BOTH parents must have at least one Kahl albino mutant gene. Otherwise, none of the babies would be able to show the Kahl albino condition. The same is true for Sharp albino. And erythristic.

Here is an analogy. You need two motorcycle wheels for a motorcycle and two bicycle wheels for a bicycle. If you buy a motorcycle wheel at one shop and a bicycle wheel at a second shop, you don't have either a complete bicycle or a complete motorcycle. Think of the Kahl albino gene as one type of wheel and the Sharp albino gene as the other type of wheel.

Hope that helps.

Paul Hollander

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