>My male is from a Anery 66% het snow to a Snow.
>My female is from an Anery het snow to Anery het snow

Your male is anerythristic and heterozygous albino (AKA anery het snow).

Your female is anerythristic and 66% probability heterozygous albino (AKA anery 66% probability het snow).

All their babies will be anerythristic. I would breed your two snakes and see if any snows turn up. If you get at least 20 babies, and none of the babies are snow, then the female has a greater than 99% probability of not being heterozygous albino. If one or more snows are born, then the female is heterozygous albino, too. Statistically, if the female is heterozygous albino, then a quarter of the babies would be snow, and the rest would be anerythristics that are 66% probability heterozygous albino. If the female is NOT heterozygous albino, then all of the babies would be anerythristic and 50% probability heterozygous albino.

Breeding an albino to an anerythristic that is heterozygous albino would produce (statistically) 1/2 albino hetrozygous anerythristic and 1/2 heterozygous albino heterozygous anerythristic (looks normal).

To get snows, both parents must have at least one albino mutant gene and at least one anerythristic mutant gene. If your goal is to produce snows, then you can do it by mating your male to a snow or an albino heterozygous anerythristic or an anerythristic heterozygous albino or a heterozygous albino heterozygous anerythristic. The cheapest way to produce snows now is for your female to be to be anerythristic heterozygous albino.

Hope this helps.

Paul Hollander

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