Posted by:
Paul Hollander
at Wed Mar 8 18:05:16 2006 [ Email Message ] [ Show All Posts by Paul Hollander ]
>Okay, Let's see if I get it right. All of the look like the daddy, right?
Right. All the babies are amelanistics.
>Half of them if breed to the mom might make snows?
Right, if the half are all males. 
All the babies are at least homozygous amelanistic and heterozygous anerythristic. Mom is homozygous amelanistic and homozygous anerythristic. Lets do the cross one mutant at a time: 1. amelanistic x amelanistic --> all babies amelanistic
2. anerythristic x heterozygous anerythristic --> 1/2 anerythristic 1/2 heterozygous anerythristic
So all the babies from a snow x amelanistic, heterozygous anerythristic are amelanistic, and half are anerythristic in addition to being amelanistic (AKA snows).
>The other half breed to the dad might make blizzards? or would they all sitll look like the dad?
Any of the amelanistic female babies bred back to amelanistic dad would produce amelanistic babies. In fact, all the babies from such a mating would be amelanistics. The question is, could any of their babies be both amelanistic and charcoal (AKA blizzards). The answer is yes, if you pick a female that is heterozygous charcoal besides being amelanistic. Because 1/4 of the babies from a heterozygous charcoal x heterozygous charcoal are expected to be charcoal. Unfortunately, you can't tell an amelanistic heterozygous charcoal from an amelanistic. So save several females to get better odds of having at least one that is heterozygous charcoal.
Good luck.
Paul Hollander
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