The term "heterozygous" does not mean,"normal,carrying a recessive trait." In recessive traits,typically there is nothing visible to distiguish hets from non-gene carriers,(one possible exception may be found in Leopards ? yet to be determined conclusively.)There may sometimes be certain markers to look for,however,in non-recessive traits,(various forms of dominant transmissives.)the heterozygous individuals are clearly distinguishable from the non-gene carrying counterparts.examples include Arabesque,Motley,Salmon/Orangetail/hypo,Jungle,(variable,and sometimes less distinct.)etc...many people get the idea that when breeding a mutation to a non-gene carrier,if the trait shows up in half the litter,it means the trait is "co-dominant".In actuality,it doesn't,it means: 1.The trait in question is non-recessive. 2.The expressive individual used in the breeding trial is likely a heterozygous example of the mutation.(when breeding ANY heterozygous individual,recessive,or not,the statistical transmissive result is 50/50...for example: het albino x "normal"=50% hets/50% "normal" )....hope this helps.
-----
EMAIL

[ Hide Replies ]

• How many people agree... - JOEP123, Sat Apr 15 22:24:58 2006
• RE: How many people agree... - VolcomHerp, Sat Apr 15 23:24:07 2006
• In biology.... - NUCCIZ_BOAS, Sun Apr 16 03:49:16 2006
• In the world of genetics,101... - Rainshadow, Sun Apr 16 10:55:30 2006
• you're right - NUCCIZ_BOAS, Sun Apr 16 12:03:37 2006
• FANTASTIC REPLYS... - JOEP123, Sun Apr 16 12:24:47 2006
• Thanks to you both...also, - Rainshadow, Sun Apr 16 13:49:20 2006