then calculate the percentage odds for each genotype. WOW!

I'll stick to the computer.

Let me try and list all of the phenotypes though:
1)Wild Type
2)Blood
3)Leopard
4)Caramel Albino
5)Sharp Albino
6)Type II Anery
7)Pewter
8)Snow
9)Caramel Type II
10)Type II Leopard
11)Bloody Leopard
12)Bloody Albino
13)Bloody Caramel Albino
14)Sharp Caramel
15)Sharp Leopard

16)Sharp Albin Pewter
17)Caramel Pewter
18)Leopard Pewter
19)Caramel Bloody Sharp
20)Leopard Bloody Sharp
21)Leopard Bloody Caramel (I don't like my caramel bloody)
22)Leopard Sharp-Snow
23)Caramel Sharp-Snow
24)Leopard Caramel-Snow
25)Caramel Leopard Sharp

26)Leopard Sharp Pewter
27)Caramel Sharp Pewter
28)Leopard Caramel Pewter
29)Caramel Leopard Sharp-Snow
30)Caramel Leopard Bloody Sharp

31)Caramel Leopard Bloody Sharp-Snow. ?????

Is this right? If so, could you imagine 31 different homozygous morphs in ONE litter!

I can dream can't I

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