Posted by:
rainbowsrus
at Fri Sep 22 21:16:54 2006 [ Email Message ] [ Show All Posts by rainbowsrus ]
what I was getting at....11/16 would have a visual phenotype other than normal IF caramel and sharp are two different gene pairs. AKA 5/16 would look normal.
But, "IF" this is a tripple allele on one locus, each animal can only have two alleles and if both are paradigm, then NO normal genes exist in this pairing. Outcome would have NO normal boas at all, 25% caramel, 50% paradigm, 25% sharp .
so, easiest way to determine this genetic riddle is to breed two paradigms. if any normals pop out, then there are two seperate gene pairs that are somehow interacting. If no normals pop out, then there are three possible genes that can go into that specific gene pair.
>>Het. caramel, Het. sharp albino,
>> x
>>Het. caramel, Het. sharp albino,
>>
>>
>>6.25% WT (would look normal)
>>12.5% Het. sharp albino (would look normal)
>>6.25% Homozygous sharp albino
>>12.5% Het. caramel, (would look normal)
>>25% Het. caramel, Het. sharp albino,(Paradigm)
>>12.5% Het. caramel, Homozygous sharp albino (Paradigm)
>>6.25% Homozygous caramel
>>12.5% Homozygous caramel, Het. sharp albino (Paradigm)
>>6.25% Homozygous caramel, Homozygous sharp albino(Paradigm)
-----
Thanks,
Dave Colling
www.rainbows-r-us-reptiles.com
0.1 Wife (WC)
0.2 kids (CBB, selectively bred from good stock)
LOL, to many snakes to list, last count:
13.26 BRB
11.16 BCI
And those are only the breeders 
lots.lots.lots feeder mice and rats 
[ Hide Replies ]
|
Exactly.... - rainbowsrus, Fri Sep 22 21:16:54 2006