>100% het albino female to a DH male sunglow het for anery

A DH (double heterozygous) sunglow het (heterozygous) for anerythristic has the following genes:
a salmon mutant gene paired with a normal gene
a normal gene paired with an albino mutant gene
a normal gene paired with an anerythristic mutant gene.
This snake could also be called het salmon, het albino, het anerythristic.

The 100% het albino female has the following genes:
two copies of the normal alternative to the salmon mutant gene
a normal gene paired with an albino mutant gene
two copies of the normal alternative to the anerythristic mutant gene.

And the expected statistical results are
1/16 salmon
1/16 salmon, het anerythristic
2/16 salmon, het albino
2/16 salmon, het albino, het anerythristic
1/16 salmon, albino (AKA sunglow)
1/16 salmon, albino (AKA sunglow), het anerythristic
1/16 normal
1/16 het anerythristic (looks normal)
2/16 het albino (looks normal)
2/16 het albino, het anerythristic (looks normal)
1/16 albino
1/16 albino, het anerythristic

Note that all the salmons have a salmon mutant gene paired with a normal gene (heterozygous salmon).

Unfortunately, in a mating like this, you can't tell the het albinos from the snakes with two copies of the normal alternative to the albino mutant gene. As both parents are het albino, the nonalbinos are often called 66% probability het albinos.

And in a mating like this, you can't tell the het anerythristics from the snakes with two copies of the normal alternative to the anerythristic mutant gene. As only one parent is het anerythristic, all of the babies could be called 50% probability het anerythristics.

Final result:
3/8 salmon, 66% probability het albino, 50% probability het anerythristic
1/8 salmon, albino (AKA sunglow), 50% probability het anerythristic
3/8 normal appearance, 66% probability het albino, 50% probability het anerythristic
1/8 albino, 50% probability het anerythristic

Hope this helps.

Paul Hollander

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