Albino (visible) X Mojave would statistically produce:
50% Mojave Heterozygous for Albino
50% Normal-looking Heterozygous for Albino

However, if you breed a Normal-looking snake that is Heterozygous for Albino to a Mojave (Het Albino X Mojave) that would statistically produce:
25% Mojave Heterozygous for Albino
25% Mojave NOT Heterozygous for Albino
25% Normal-looking Heterozygous for Albino
25% Normals NOT heterozygous for Albino
...this means that all of these snakes would be referred to as "50% possible" Hets for Albino, since you can't tell by looking at them if they carry the recessive gene for Albinism. So there would be Mojaves "50% possible" Het Albino, and Normals "50% possible" Het Albino - which would not be worth as much as the known Hets.

If you are hoping to produce an Albino Mojave, you would need to breed a Mojave that is Het Albino to an animal that is either Het for Albino or Homozygous (visible) Albino.
Mojave Het Albino X Het Albino would statistically produce:
12.5% Mojave Albino
25.0% Mojave Het Albino
12.5% Mojave NOT Het Albino
12.5% Albino
25.0% Normal-looking Het Albino
12.5% Normal NOT Het Albino
Similar to the situatiion that yielded "50% possible" Hets, this produces "66% possible" Hets, since 2/3 of the animals that are not Homozygous (visible) Albino carry that gene (Het), whether they are also expressing the Mojave trait or not.

Mojave Het Albino X Albino (visible) would statistically produce:
25% Mojave Albino
25% Mojave Het Albino
25% Albino
25% Normal-looking Het Albino
Happily, this combination produces "100%" or KNOWN Hets - there is no guesswork for you or your buyers! If offspring from this breeding does not exhibit albinism, then you know that the animal carries that gene.

Good luck! I realize this is more than you asked for, but I like this stuff.
~Rebecca
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0.1 Dumeril's Boa '04 (Courtney)
1.2 Ball Pythons



0.2 American Pit Bull Terriers (40lb darling lap dogs:Brandy&Mara)

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