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Expect 1/8 of the babies to be sunglow.

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Posted by: Paul Hollander at Tue Jan 2 15:38:56 2007   [ Email Message ] [ Show All Posts by Paul Hollander ]  
   

A DH sunglow has a gene pair containing one copy of the salmon (= hypo) mutant gene and one copy of the normal version of the salmon gene. The snake also has a gene pair containing one copy of the albino mutant gene and one copy of the normal version of the albino gene. For what it's worth, the normal version of the salmon gene is not the same as the normal version of the albino gene.



A 100% het albino (= het albino) has a gene pair containing one copy of the albino mutant gene and one copy of the normal version of the albino gene. The snake also has a gene pair containing two copies of the normal version of the salmon gene.



The expected breeding results from a 100% het albino X DH Sunglow:

3/8 normal looking (66% probability het albino)

3/8 salmon (= hypo) (66% probability het albino)

1/8 salmon albino (= sunglow)

1/8 albino



If you have more time than money, half of the babies from a DH sunglow mated to a normal boa would be salmon, 50% probability albino and the rest of the babies would be normal-looking, 50% probability albino. These could be sold or swapped for an albino or het albino.



Good luck.



Paul Hollander


   

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