I agree with the explanation all the way to the end:

"If you crossed the double hets, you'd only have a 1/16 chance of getting albinos"

The 1/16 chance would be for an animal that was homozygous for BOTH forms of albinism. Math gets a little complicated but looking at each form of albinism seperately there would be a 25% chance being homozygous for that form of albinism. So each would have 4/16ths probability. The complication comes with the overlapping 1/4 probability of also being homozygous for the other form of albinism.

Bottom line, crossing DH's for both forms of albinism would result in:

1/16 homozygous for both
3/16 homozygous for "Kahl" possible het for "Sharp"
3/16 Homozygous for "Sharp" possible het for "Kahl"
(all of which would look more or less alike just like any litter including albinos or 7/16 probability of "abino" with unknown specific genetic makeup)

9/16 Normal possible het for "kahl" and/or possible het for "Sharp"
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC)
0.2 kids (CBB, selectively bred from good stock)

LOL, to many snakes to list, last count:
12.25 BRB
12.14 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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