>I wanted to know what morphs will make snow boas?



Snow is a combination of Kahl albino and anerythristic. Both mutant genes are recessive to the respective normal genes, which means that, to get a snow, both parents must have at least one albino mutant gene and one anerythristic mutant gene. In other words, both parents must be in the following list:



Kahl albino, anerythristic (snow)

Kahl albino, heterozygous anerythristic

anerythristic, heterozygous Kahl albino,

heterozygous Kahl albino, heterozygous anerythristic



To make Sharp snows, use a Sharp albino mutant gene instead of a Kahl albino mutant gene in the above list.



>Also what morphs will make moonglows? and what are the difference between them.



Moonglow is a combination of salmon (AKA hypo), Kahl albino, and anerythristic.



>Last question what are the three genes in the triple hets for moonglow, and what would you get if you bred two triple hets together?



A triple het for moonglow has a Kahl albino mutant gene paired with the normal version of the gene, an anerythristic mutant gene paired with the normal version of the gene, and a salmon mutant gene paired with the normal version of the gene. The salmon mutant gene is dominant to the normal version of the gene, which means that both parents would have the salmon appearance.



It is too long to list all the genetic types from this cross. I will just list what the babies would look like and the expected fractions:



27/64 salmon (either two salmon genes or one salmon gene paired with a normal gene), may be heterozygous albino, heterozygous anerythristic, both, or neither.



9/64 normal looking, may be heterozygous albino, heterozygous anerythristic, both, or neither.



9/64 salmon (either two salmon genes or one salmon gene paired with a normal gene), albino, may or may not be heterozygous anerythristic. These are sunglows.



9/64 salmon (either two salmon genes or one salmon gene paired with a normal gene), anerythristic, may or may not be heterozygous albino.



3/64 albino, may or may not be heterozygous anerythristic.



3/64 anerythristic, may or may not be heterozygous albino.



3/64 salmon (either two salmon genes or one salmon gene paired with a normal gene), albino, anerythristic. These are moonglows.



1/64 albino, anerythristic (snow)



As salmon is a dominant gene, only one parent must possess the salmon mutant in order to get moonglow.



Hope this helps.



Paul Hollander

[ Show Entire Thread ]