Posted by:
Paul Hollander
at Fri Jun 1 17:09:30 2007 [ Email Message ] [ Show All Posts by Paul Hollander ]
>What would a I get from;
>
>DH Coral Sunglow (kahl) X Albino Het Snow (kahl)
As far as I know, the coral effect has to be selected for and is not the result of a single mutant gene. There is likely to be some coral in some of the babies, but I can't predict how much or in how many.
A DH Sunglow has a Kahl albino mutant gene paired with a normal gene (albino//normal) and a salmon (AKA hypo) mutant gene paired with a normal gene (salmon//normal). All the thousands of other gene pairs in its genome are either wild type (AKA normal) or cannot be distinguished from wild type with our present methods. One of those normal gene pairs corresponds to the albino het snow's anerythristic//normal gene pair.
An albino het snow has a pair of Kahl albino mutant genes and an anerythristic mutant gene paired with a normal gene (anerythristic//normal). All the thousands of other gene pairs in its genome are either wild type (AKA normal) or cannot be distinguished from wild type with our present methods. One of those normal gene pairs corresponds to the sunglow's salmon//normal gene pair.
So there are three gene pairs to look at
albino//normal x albino//albino -->
1/2 albino//albino = albino
1/2 albino//normal = het albino, which looks normal
Salmon//normal x normal//normal -->
1/2 salmon//normal = salmon
1/2 normal//normal = normal
normal//normal x anerythristic//normal -->
1/2 normal//normal = normal
1/2 anerythristic//normal = het anerythristic, which looks normal
So half of the babies would be albino. And half of the babies would be salmon. The babies that are both salmon and albino are sunglows. None of the babies would be anerythristic, snow, or moonglow.
Final summary, with the expected fractions:
DH Coral Sunglow (kahl) X Albino Het Snow (kahl) -->
1/4 albino (50% probability het anerythristic)
1/4 sunglow (50% probability het anerythristic)
1/4 salmon (50% probability het anerythristic)
1/4 normal (50% probability het anerythristic)
>Also if you wouldn't mind;
>
>DH Coral Sunglow (kahl) X Sharp Albino
The coral result is likely to be the same as in the first mating.
We've got the DH sunglow's gene pairs. It has a pair of normal genes where the Sharp albino has a pair of Sharp albino genes. And the Sharp albino has pairs of normal genes corresponding to the DH sunglow's salmon//normal and albino//normal gene pairs.
Final result, including fractions:
DH Coral Sunglow (kahl) X Sharp Albino -->
1/2 salmon, heterozygous Sharp albino, 50% probability het Kahl albino. These look like salmons.
1/2 heterozygous Sharp albino, 50% probability het Kahl albino. These look normal.
>I already have the male DH Coral Sunglow, just trying to figure out a nice female. I assume a Normal Het Sharp Albino would give me the same results as a Sharp Albino, or am I wrong?
Looks of the babies would be the same, but the genes would be slightly different.
Result of this pairing is
1/2 salmon, 50% probability het Sharp albino, 50% probability het Kahl albino. These look like salmons.
1/2 50% probability het Sharp albino, 50% probability het Kahl albino. All of these look normal, and some would not carry either albino mutant.
In my opinion, the mating of choice is DH Coral Sunglow (kahl) X Albino Het Snow (kahl). YMMV.
Paul Hollander
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RE: DH Coral Sunglow X Albino Het Snow - Paul Hollander, Fri Jun 1 17:09:30 2007
