Thanks Paul, I figured I had not invented the wheel, just reinvented it. I was hoping you'd chime in.

The other thing I really like about this method is it ALSO works on codominant morphs. For example:

Albino Motley x het albino Motley

albino x het albino
1/2 albino
1/2 het albino

Motley x Motley
1/4 homozygous motley (aka super motley)
1/2 motley
1/4 normal

Total phenotypes = 2 x 3 = 6

Albino super motley = 1/2 x 1/4 = 1/8
Albino Motley = 1/2 x 1/2 = 1/4
Albino = 1/2 x 1/4 = 1/8
Het Albino super motley = 1/2 x 1/4 = 1/8
Het Albino Motley = 1/2 x 1/2 = 1/4
Het Albino = 1/2 x 1/4 = 1/8
-----
Thanks,


Dave Colling

www.rainbows-r-us-reptiles.com



0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
21.29 BRB
19.19 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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