>>Thanks Paul, I figured I had not invented the wheel, just reinvented it. I was hoping you'd chime in.
>>
>>The other thing I really like about this method is it ALSO works on codominant morphs. For example:
>>
>>Albino Motley x het albino Motley
>>
>>albino x het albino
>>1/2 albino
>>1/2 het albino
>>
>>Motley x Motley
>>1/4 homozygous motley (aka super motley)
>>1/2 motley
>>1/4 normal
>>
>>Total phenotypes = 2 x 3 = 6
>>
>>Albino super motley = 1/2 x 1/4 = 1/8
>>Albino Motley = 1/2 x 1/2 = 1/4
>>Albino = 1/2 x 1/4 = 1/8
>>Het Albino super motley = 1/2 x 1/4 = 1/8
>>Het Albino Motley = 1/2 x 1/2 = 1/4
>>Het Albino = 1/2 x 1/4 = 1/8
>>-----
>>Thanks,
>>
>>
>>Dave Colling
>>
>>www.rainbows-r-us-reptiles.com
>>
>>
>>
>>0.1 Wife (WC and still very fiesty)
>>0.2 kids (CBB, a big part of our selective breeding program)
>>
>>LOL, to many snakes to list, last count:
>>21.29 BRB
>>19.19 BCI
>>And those are only the breeders
>>
>>lots.lots.lots feeder mice and rats

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