Posted by:
rainbowsrus
at Tue Jun 26 17:58:58 2007 [ Email Message ] [ Show All Posts by rainbowsrus ]
>>>>Thanks Paul, I figured I had not invented the wheel, just reinvented it. I was hoping you'd chime in.
>>>>
>>>>The other thing I really like about this method is it ALSO works on codominant morphs. For example:
>>>>
>>>>Albino Motley x het albino Motley
>>>>
>>>>albino x het albino
>>>>1/2 albino
>>>>1/2 het albino
>>>>
>>>>Motley x Motley
>>>>1/4 homozygous motley (aka super motley)
>>>>1/2 motley
>>>>1/4 normal
>>>>
>>>>Total phenotypes = 2 x 3 = 6
>>>>
>>>>Albino super motley = 1/2 x 1/4 = 1/8
>>>>Albino Motley = 1/2 x 1/2 = 1/4
>>>>Albino = 1/2 x 1/4 = 1/8
>>>>Het Albino super motley = 1/2 x 1/4 = 1/8
>>>>Het Albino Motley = 1/2 x 1/2 = 1/4
>>>>Het Albino = 1/2 x 1/4 = 1/8
>>>>-----
>>>>Thanks,
>>>>
>>>>
>>>>Dave Colling
>>>>
>>>>www.rainbows-r-us-reptiles.com
>>>>
>>>>
>>>>
>>>>0.1 Wife (WC and still very fiesty)
>>>>0.2 kids (CBB, a big part of our selective breeding program)
>>>>
>>>>LOL, to many snakes to list, last count:
>>>>21.29 BRB
>>>>19.19 BCI
>>>>And those are only the breeders
>>>>
>>>>lots.lots.lots feeder mice and rats
-----
Thanks,
Dave Colling
www.rainbows-r-us-reptiles.com
0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)
LOL, to many snakes to list, last count:
21.29 BRB
19.19 BCI
And those are only the breeders 
lots.lots.lots feeder mice and rats  
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