Posted by:
rainbowsrus
at Tue Jun 26 17:58:58 2007 [ Email Message ] [ Show All Posts by rainbowsrus ]
>>>>Thanks Paul, I figured I had not invented the wheel, just reinvented it. I was hoping you'd chime in. >>>> >>>>The other thing I really like about this method is it ALSO works on codominant morphs. For example: >>>> >>>>Albino Motley x het albino Motley >>>> >>>>albino x het albino >>>>1/2 albino >>>>1/2 het albino >>>> >>>>Motley x Motley >>>>1/4 homozygous motley (aka super motley) >>>>1/2 motley >>>>1/4 normal >>>> >>>>Total phenotypes = 2 x 3 = 6 >>>> >>>>Albino super motley = 1/2 x 1/4 = 1/8 >>>>Albino Motley = 1/2 x 1/2 = 1/4 >>>>Albino = 1/2 x 1/4 = 1/8 >>>>Het Albino super motley = 1/2 x 1/4 = 1/8 >>>>Het Albino Motley = 1/2 x 1/2 = 1/4 >>>>Het Albino = 1/2 x 1/4 = 1/8 >>>>----- >>>>Thanks, >>>> >>>> >>>>Dave Colling >>>> >>>>www.rainbows-r-us-reptiles.com >>>> >>>> >>>> >>>>0.1 Wife (WC and still very fiesty) >>>>0.2 kids (CBB, a big part of our selective breeding program) >>>> >>>>LOL, to many snakes to list, last count: >>>>21.29 BRB >>>>19.19 BCI >>>>And those are only the breeders >>>> >>>>lots.lots.lots feeder mice and rats ----- Thanks,
Dave Colling
www.rainbows-r-us-reptiles.com
0.1 Wife (WC and still very fiesty) 0.2 kids (CBB, a big part of our selective breeding program)
LOL, to many snakes to list, last count: 21.29 BRB 19.19 BCI And those are only the breeders
lots.lots.lots feeder mice and rats
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