Posted by:
rainbowsrus
at Thu Jun 28 00:43:38 2007 [ Email Message ] [ Show All Posts by rainbowsrus ]
Paradigm is believed to be three possible genes within one gene pair, Normal, Boawoman Caramel, and sharp albino.
2x boawoman caramel genes = visual boawoman caramel
2x Sharp albino genes = visual Sharp albino
1x boawoman plus 1x sharp albino = paradigm
1x normal plus 1x Sharp albino = het sharp albino
1x normal plus 1x boawoman caramel = het boawoman caramel
so, to break down Pauls example:
paradigm x het Sharp albino -->
1/2 normal (50% probability het Sharp albino, 50% probability het boawoman caramel)
1/4 paradigm
1/4 Sharp albino
The paradigm would have one boawoman caramel paired with a sharp albino gene.
The het sharp albino would have a sharp albino paired with a normal.
Using the het sharp as a starting point, 1/2 of the babies would get a normal gene, the other gene supplied by the paradigm would be 50/50 boawoman caramel / sharp albino or
1/2 normal (50% het Sharp albino, 50% het boawoman caramel)
the other half of the babies would get the sharp albino gene and again would get 50/50 caramel/albino from the other parent or:
1/4 paradigm (sharp albino paired with boawoman caramel)
1/4 Sharp albino (sharp albino paired with sharp albino) ----- Thanks,
Dave Colling

www.rainbows-r-us-reptiles.com
0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)
LOL, to many snakes to list, last count:
21.29 BRB
19.19 BCI
And those are only the breeders 
lots.lots.lots feeder mice and rats   
[ Hide Replies ]
|