Albino is a recessive trait where an offspring has to get one copy of the recessive gene from each parent in order for the trait to show. Since each parent is a het, they will each pass on an albino gene to 1/2 of their offspring. Tpo get a fianl result you have to multpily the probabilities or 1/2 x 1/2 = 1/4 of the babies would be albino. Of course real woirld actuals can and do vary. The remainder of the litter would be 1/4 het albino from dad, 1/4 het albino from mom and 1/4 normal from both but since you can't visully tell them apart, they're called 66% hets or two out of three chance any individula is a het.


Anery is also a recessive trait so look at each trait seperately....

anery x normal = all 100% hets

Albino x het albino = 1/2 albino, 1/2 het albino.

combined back together =

1/2 albino, het anery (or albino het snow)
1/2 het albino, het anery (or DH snow)


IMO a great choi=ce is one where the expected offspring fall inot several visually distinguishable phenotypes like

Anery het albino x albino et anery =
1/4 snow
1/4 albino het anery
1/4 anery het albino
1/4 DH snows

To maximize the number of phenotypes from a given pairing, look at each morph trait seperately and have them follow these rules:

Recessive trait - one parent homozygous (or showing the trait) and the other het (does not matter which is which)

Dominant trait - one parent being het, other normal

Codominant trait - both parent being het
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Thanks,


Dave Colling

www.rainbows-r-us-reptiles.com



0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
24.36 BRB
19.19 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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