The one real problem is figuring out what you have.

If you take Brian's statement that it was done and got nothing but normals (BTW, I heard this directly from Brian in phone conversations we've had) as true, then it's fair to say the genes are not compatible.

If you agree with the genes being incompatible, then breeding would follow standard DH rules EXCEPT all the phenotypes are merged into two possible phenotypical outcomes, albino (unknown strain) or normal poss hets for either or both. In numbers, out of a litter of 16 if punnet square exactly followed (as if that'd ever happen)...

One other assumption, that you could not tell the kahl's and sharps apart from each other and that the double albino also was indistinguishable from the rest.


1 Kahl and Sharp combined albino
2 Kahl albino, het sharp
1 Kahl albino
2 Sharp albino het Kahl
1 Sharp albino
9 normals 66$ het Kahl and 66% het sharp

But, if you couldn't tell the albino's apart, then it'd be
7 albinos some kahl, some sharp and one both
9 normals


The real problem comes in proving out and finding the double strain albino and the multitude of unknown status babies that would produce. You would have to breed each of the 7 albinos twice to prove it's status, once to a Kahl and once to a Sharp. Againif all went perfectly according the punnet with litters of 16 you would have...

48 Kahl albino het sharp
32 Kahl albino pos het sharp
16 het kahl pos het sharp
32 DH kahl/sharp
16 het sharp pos het kahl
32 sharp albino pos het kahl
48 sharp albino het kahl

All that and you've only produced and proven one kahl/sharp albino. (240 babies later)
-----
Thanks,


Dave Colling

www.rainbows-r-us-reptiles.com



0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
24.36 BRB
19.19 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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