Posted by:
Paul Hollander
at Fri Mar 7 18:30:38 2008 [ Email Message ] [ Show All Posts by Paul Hollander ]
>If both alleles of a gene are present,then the animal is homozygous for the gene.If only one is present,then the animal is heterozygous for the gene.
>pastels yellowbellys and mojaves are visable hets (therefore they each have one allele,same as recessive traits with het albino,hypo,clown,etc.)
This does not compute.
A het albino is heterozygous because it has an albino mutant gene paired with a normal gene. The albino mutant gene is one allele, and the normal gene is another allele. That makes two alleles, not one.
A pastel is heterozygous because it has a pastel mutant gene paired with a normal gene. Again, that makes two alleles, not one. Same for yellowbellies and mojaves.
An albino has two copies of one allele, the albino mutant gene, so it is homozygous albino. A super pastel has two copies of one allele, the pastel mutant gene, so it is homozygous pastel. A normal snake has two copies of the normal gene where the albino has albino mutant genes. The normal snake also has two copies of the normal gene where the super pastel has pastel mutant genes. This makes the normal snake homozygous normal at these locations in its genome.
Paul Hollander
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