>>>If both mutant alleles of a gene are present,then the animal is homozygous for the gene.If only one mutant allele is present(and one normal allele),then the animal is heterozygous for the gene.

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>>>pastels yellowbellys and mojaves are visable hets (therefore they each have one mutant allele(and one norma allele),same as recessive traits with het albino,hypo,clown,etc.)

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>>This does not compute.

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>>A het albino is heterozygous because it has an albino mutant gene paired with a normal gene. The albino mutant gene is one allele, and the normal gene is another allele. That makes two alleles, not one.

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>>A pastel is heterozygous because it has a pastel mutant gene paired with a normal gene. Again, that makes two alleles, not one. Same for yellowbellies and mojaves.

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>>An albino has two copies of one allele, the albino mutant gene, so it is homozygous albino. A super pastel has two copies of one allele, the pastel mutant gene, so it is homozygous pastel. A normal snake has two copies of the normal gene where the albino has albino mutant genes. The normal snake also has two copies of the normal gene where the super pastel has pastel mutant genes. This makes the normal snake homozygous normal at these locations in its genome.

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>>Paul Hollander









ok..i do now see the communication error on my part here,by not including the normal alleles involved in the situation.



If both(mutant)alleles of a gene are present,then the animal is homozygous for the gene.If only one(mutant)allele is present(and one normal allele),then the animal is heterozygous for the gene.



Pastels yellowbellys and mojaves are visable hets..Therefore they each have one mutant allele(and one normal allele),same as recessive traits with het albino,hypo,clown,etc.



Is that what your observing here Paul?

(My omission of the normal alleles due to my thinking in a goal orientation.)
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Charles Glaspie

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