The best way to get odds is with the Advanced Genetics Wizard (http://www.geneticswizard.com/f_start_genetics_wizard.asp), but just like any computer it is only as smart as the person inputting the data. What confuses some people is that they mark "normal/wildtype" as an abnormal trait.



I'll do a quick one for you: triple het moonglow x jungle



How many abnormal traits are present? Albino, hypo, anery, and jungle, so 4.



Let's say dad is the triple het and mom is the jungle. So dad is het albino, het anery, and het hypo (unless he's a super, then he's a homozygous hypo) and for jungle you'll put wildtype because there is no jungle gene present in him.



For the jungle mom you will have wildtype checked for albino, anery, and hypo and het for jungle (again, unless she's a super). The D and C superscripts are to denote dominant and codominant traits, but I feel comfortable enough with how the morphs work to not use them.



I always check to round to 2 decimal places to keep things simple and voila, you've got it then.



Here is what you should get in a perfect world:



Het. Albino, Het. Anery, Het. Hypo,

x

Het. Jungle,



6.25% WT

6.25% Het. Jungle,

6.25% Het. Hypo,

6.25% Het. Hypo, Het. Jungle,

6.25% Het. Anery,

6.25% Het. Anery, Het. Jungle,

6.25% Het. Anery, Het. Hypo,

6.25% Het. Anery, Het. Hypo, Het. Jungle,

6.25% Het. Albino,

6.25% Het. Albino, Het. Jungle,

6.25% Het. Albino, Het. Hypo,

6.25% Het. Albino, Het. Hypo, Het. Jungle,

6.25% Het. Albino, Het. Anery,

6.25% Het. Albino, Het. Anery, Het. Jungle,

6.25% Het. Albino, Het. Anery, Het. Hypo,

6.25% Het. Albino, Het. Anery, Het. Hypo, Het. Jungle,



You've chosen to round percentages

to a maximum of 2 decimal places.

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