Posted by:
jhsulliv
at Mon Oct 6 20:42:00 2008 [ Email Message ] [ Show All Posts by jhsulliv ]
Just because I'm visual and also like long explanations, see if this helps. I went through it a little fast so post if you need any clarification.
Let's let "a" stand for albino and "H" stand for hypo. Remember that the dominant trait is always the capital letter so that "A" and "h" are normal/wild-type and "a" is albino since it's recessive and "H" is hypo since it's dominant. Just for example's sake: AA = normal/wildtype, Aa = het albino, aa = albino. HH = super hypo, Hh = hypo, hh = normal/wildtype.
You have a normal het for albino: Aa. She could be het for anery, but the only way to know if she is in fact het for anery is to prove her out. Until then there is no probability to list there because she either is or isn't het for anery. Let's assume she isn't until proven otherwise.
You cross her to a hypo, Hh. Since we are dealing with TWO abnormal traits you have to account for all of them in your equation so you have:
Aahh x AAHh
Do a Punnett square, if you don't know how I can go through it with you or you can Google it and you will end up (in a perfect world) with::
25% normals (wild-type)
25% normals het albino
25% hypos
25% hypos het albino
The Genetics Wizard is a great tool to use as well. No math or Punnett Squares needed!
http://www.geneticswizard.com/f_start_genetics_wizard.asp
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RE: question on genetics - jhsulliv, Mon Oct 6 20:42:00 2008