I do these all in my head now and is actually fairly easy for one specific outcome.

Take each morph seperatley. I assume your talking TH (hypo/albino/anery) x TH (same)

Het hypo x het hypo =
3/4 hypo (33% chance super)
1/4 normal

Het Albino x het Albino =
1/4 albino
3/4 normal (66% chance het)

Het Anery x het Anery =
1/4 Anery
3/4 normal (66% chance het)

From there pick an outcome and multiply the associated percentages (remember there must be one factor for each morph even if that specific outcome is visually normal)

Moonglow =
3/4 x 1/4 x 1/4 = 3/64

Snow =
1/4 x 1/4 x 1/4 = 1/64

Sunglow (66% het Anery) =
3/4 x 1/4 x 3/4 = 9/64

Albino (66% het Anery)=
1/4 x 1/4 x 3/4 = 3/64

Ghost (66% het Albino) =
3/4 x 3/4 x 1/4 = 9/64

Anery (66% het Albino) =
1/4 x 3/4 x 1/4 = 3/64

Hypo (66% het Albino and 66% het Anery) =
3/4 x 3/4 x 3/4 = 27/64

Normal (66% het Albino and 66% het Anery) =
1/4 x 3/4 x 3/4 = 9/64


Sum of all the above is 64/64

All done in my head, no paper, no genetics calculator etc.

AND, this method works for ANY combination of as MANY or as FEW morphs as you want... Of course it's easier to pick out one or two desired outcomes than to do each and every possible outcome.

For example Motley Sunglow het Anery x Jungle TH Moonglow

What are the odds of getting a Motley Jungle Moonglow?

Het Motley x normal = 1/2
Het Hypo x Het Hypo = 3/4
Albino x het Albino = 1/2
Het Anery x Het Anery = 1/4
Normal x Het Jungle = 1/2

1/2 x 3/4 x 1/2 x 1/4 x 1/2 = 3/128
-----
Thanks,


Dave Colling

www.rainbows-r-us-reptiles.com



0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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