That is impressive! I'm not sure if that formula exists because we don't know what is co-dom and what is simple recessive. If every combination yielded 4 morphs, that would be 1122*4, but since you have to factor in the crosses that give the same thing, like het albinoX albino, you get some het's and het albino X het albino = some het's... you would have repeats. If it was separated between co-doms, and simple recessive there might be a way... but the answer is C) none of the above/not enough information I hope that makes sense!
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-Madison
2.1 normal bp
1.0 albino bp
0.1 het albino bp
1.0 albino burm

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