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Posted by: cyrus7 at Tue Nov 11 23:12:35 2008 [ Email Message ] [ Show All Posts by cyrus7 ] That is impressive! I'm not sure if that formula exists because we don't know what is co-dom and what is simple recessive. If every combination yielded 4 morphs, that would be 1122*4, but since you have to factor in the crosses that give the same thing, like het albinoX albino, you get some het's and het albino X het albino = some het's... you would have repeats. If it was separated between co-doms, and simple recessive there might be a way... but the answer is C) none of the above/not enough information I hope that makes sense! [ Hide Replies ]
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>> Next topic: Albino lock-up - stevebp, Tue Nov 11 16:12:25 2008 << Previous topic: Some of my 08s "are these normals?" lol - 414reptiles, Tue Nov 11 12:42:18 2008 |
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