Your plan of Ghost het Albino x Albino het Anery (or the alternate) IMO is a very sound one. Like you said, 8 phenotypes and even more than that, 1/8 probability on each one. AND (big plus) each phenotype has defined genetics, no "possible hets" in the group.

Your second lower probability alternative Albino het Anery x TH Moonglow. Can produce the same 8 phenotypes (in lower percentages) but any time Anery is not visible, it's a possible het. You could take that a step further and go DH Snow x TH Moonglow But even more possible hets will come out. Don't get me wrong, I have a TH x DH pairing going on and I do expect the lower odds, just need to know / accept that going in.


Your initial pairing is what I call a prime pairing, multiple visual outcomes with known genetics in each baby by simple visual phenotype. To get there with the most possible phenotypical outcomes you need parents with......

Recessive traits - one parent visual, the other a het

Dominant traits - one parent visual, the other parent normal

1) Codominant traits - three ways to go...
Most possible phenotypes - Both parents visual hets
2) Most possible visual codom morphs - one parent visual het, one parent a super or homozygous morph
3) Least expensive investment - one parent visual het, other parent normal.

In your example there are four ways to get the same prime pairing outcome...

Moonglow x DH Snow
Snow x TH Moonglow
Ghost het Albino x Albino het Anery
Sunglow het Anery x Anery het Albino
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Thanks,


Dave Colling

www.rainbows-r-us-reptiles.com



0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

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