Posted by:
rainbowsrus
at Sun Mar 15 14:32:43 2009 [ Email Message ] [ Show All Posts by rainbowsrus ]
Too many ways to list them all. A moonglow is a five gene wonder. One hypo gene and two each Albino and Anery genes. Since each parent can only supply one gene of any type, both parents have to have both Anery and Albino genes and at least one has to have a Hypo gene.
Minimal pairing is DH Snow (het Albino, het Anery) X TH Moonglow (Het Hypo, Het Albino, Het Anery)
And YES, het Anery is correct, being a dominant trait it will express with only one gene but can still be heterozygous meaning two different genes in a locus.
Those paretns DH x TH have a total of five morph genes present. The bare minimum as if all five pass on to one baby, it's a moonglow.
To increase your odds get animals with more genes present.
Like......
Albino het Anery x Ghost het Anery
or
Sunglow het Anery x Anery het Albino
would both be great pairings as each baby would have known genetics. ----- Thanks,
Dave Colling

www.rainbows-r-us-reptiles.com
0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)
LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders 
lots.lots.lots feeder mice and rats   
[ Show Entire Thread ]
|