In this scenario you don't need to use a punnet square set-up for a double recessive breeding. It is a recessive and co-dominant breeding so your chances are actually better than 1 in 16 to create the panda pied.



In using the breedings you have already used the parents are both going to be black pastels 100% het. pied. So you would break into punnet squares for a het x het breeding; giving you 1 pied, 2-100% het, and 1 normal. ( you won't know which 2 of the 3 normal looking babies are the 100% het's, therefore all 3 are labeled 66% het for pied).



Now you set-up your squares for your black pastel x black pastel breeding, in which your babies should turn out: 1 super black pastel, 2 black pastels and 1 normal.



So now when it gets tallied up after overlapping your 2 sets of punnet squares you are THEORETICALLY going to hatch out 1 normal, 2 black pastels and 1 super black pastel with 1 of those 4 animals being a pied. This is where a little luck comes into play in getting the pied gene to line-up with the 2 black pastel genes creating the panda pied.



It's not as involved as a double recessive gene but a lotta luck is needed in the beeding.

[ Show Entire Thread ]