This would have been a question more appropriate for the morph discussion forum. You may fair better asking for good tutorial sites. It's a very involved explanation. Basically you'll end up with all hets. All animals have sets of genes. Ever seen a picture of the twisting DNA chain? One dot on one side and the other dot on the other side connected by a bar? Those dots represent those genes. You get one dot from the mother and the other dot from the father. Simple recessive genes require both dots to be the same to be seen. An albino animal has both albino dots. If bred with something that don't have any albino dot it pairs a normal dot with the albino so every offspring has one of each appearing normal. So in your pairing the albino will be able to offer the albino gene yet the hypo must give a normal gene to pair with the albino gene because it don't have any albino gene to pair with it. Unless it's het for albino. And the Hypo will be able to offer the hypo gene and the albino will have to match it with a normal gene because it don't have a hypo gene to pair with it. The albino and hypo genes are not in the same location on the chain of dna so they work completely independently. I know it's confusing and sometimes picture guides help. I tried my best to explain it as simplified as I could. The best thing you can do is just research the web and read everything you find on cornsnake genetics.

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