Posted by:
CBH
at Wed Nov 17 09:03:17 2010 [ Email Message ] [ Show All Posts by CBH ]
Example 1 Axanthism in Heterodon nasicus for instance has been discover from at least 2 locales (i.e. BHB line and Russo line). When crossed, we would expect normal offspring in the F1 generation if the gene(s) controlling axanthism are on 2 separate loci. The offspring in this scenario would be doubly heterozygous (heterozygous at both loci). However, it has been proven that crossing the two lines will produce axanthic individuals, thus we can deduce that it is the same gene at the same location on the chromosome (locus) controlling the mutation.
Example 2 There are several lines of amelanism in H. nasicus and we know that at least some of these ‘lines’ are not compatible. For instance, if you breed a T-plus albino (traditional hypo), to a T-minus albino (traditional albino), you will get ALL normal looking babies (these babies would be doubly heterozygous). This is because the genes that control the reduction in melanin are on two separate loci.
Troy- Feel free to contact me if you have more questions or would just like to discuss genetics.
-Chris ----- Christopher E. Smith Contact Captive Bred Herps Wildlife Research & Consulting Services, LLC
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