Posted by:
Rextiles
at Wed Aug 24 17:42:58 2011 [ Email Message ] [ Show All Posts by Rextiles ]
The Anaconda is a co-dom pattern morph created by Brent Bumgardner.
Let's be a little more clear about this. Brent didn't create the Anaconda morph, he discovered and proved the Anaconda gene. To create something, you have to have intent. Being that the Anaconda gene came into being unexpectedly, there was no intent. Now, Brent did create morphs like the Amelanistic Superconda, he had intent and did selective breeding trials to create that specific morph.
In regards to the Anaconda Codominant trait, it is the heterozygous form of the Superconda (Patternless). It's not much different than having Recessive hets except there is a visual phenotype for the Codominant het which is the Anaconda phenotype.
In Recessive traits, there can only be two phenotypes, that of the Normal (which is the typical dominant trait) and the Recessive trait (We'll use Amelanistic as example) :
Normal = AA
Amelanistic = aa
Normal heterozygous for Amelanism = Aa
When we breed a Normal to a Recessive trait animal, we get 100% hets (Aa) but they all look Normal. This is because the Normal trait is dominant and will override the Recessive gene in the heterozygous form.
However, in Codominant traits (We'll use the Anaconda/Superconda trait as an example), there are three phenotypes:
Normal = AA
Superconda = aa
Anaconda (Codominant heterozygote)= Aa
When we breed a Normal to a Superconda, we also get 100% heterozygous animals (Aa), the big difference is that both traits are dominant and therefore are competing against each other to show their individual traits creating the Anaconda phenotype.
You can use Punnett squares or the FOIL (First, Outside, Inside, Last) method to determine heritable ratios. Let's use the FOIL method to determine Superconda/Anaconda ratios:
AA x aa = Aa, Aa, Aa, Aa = 4 Anaconda.
AA x Aa = AA, Aa, AA, Aa = 2 Normal, 2 Anaconda.
Aa x Aa = AA, Aa, aA (Same as Aa), aa = 1 Normal, 2 Anaconda, 1 Superconda.
Aa x aa = Aa, Aa, aa, aa = 2 Anaconda, 2 Superconda
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Troy Rexroth
Rextiles
[ Hide Replies ]
- Anaconda? - texasviper619, Wed Aug 24 13:14:08 2011
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RE: Anaconda? - Rextiles, Wed Aug 24 17:42:58 2011