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Posted by: Paul Hollander at Sat Nov 22 16:45:12 2003 [ Email Message ] [ Show All Posts by Paul Hollander ] From what I've been told, caramel and anerythristic are independant mutants. And both are recessive to their respective normal (AKA wild type) alleles. So caramel x anerythristic produces all normal looking babies that are heterozygous anerythristic, heterozygous caramel. [ Hide Replies ]
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