What happens when a Leucistic and a Rusty are crossed to each other?



******= you should get 50% Rustys & 50% Leucistics.





Mike, the other parent to the cross was a D.B. Sunglow (we also believe that it is an albino Rusty). So a Leucistic crossed to an albino Rusty gave all Rusties. Does this make any sense?

******= yes, all the animals are Het. for Leucistic - that is why they are all Ruistys.





If you take a normal to a rusty, you will get 50:50 babies. If you then take two of the NORMAL ones and cross them to each other, will any rusties come of that?



******No - the normals do not carry any of the recessive genes for leucisim. If they did, they would be a Rusty. No Rustys would be present in the offspring as a result of the breeding in question because the Rusty is co-dominant (which is prob. not the actual def. to a geneticist but part of the vocab. of a snake breeder). In order top produce Rustys, you need a rusty or Leucistic as one of the parents.

Rusty X wild-type = 50% Rusty & 50% wild-type

Rusty X Rusty = 25% Leucistic, 25% wild-type, & 50% Rusty

Leucsitic X Normal = 100% Rusty

Leucistic X Rusty = 50% Leuc. & 50% Rusty

Leucistic X Leucistic = 100% Leucistic





If so, doesn't this indicate that Rusty can be heterozygous?



****** Yes - Rustys = Het. Leucistic



What also doesn't make sense is where the first Sunglow came from. Darin said he took a baby from the ORIGINAL Leucistic's wild breeding clutch and crossed it back to mom. This is where the Sunglow came from.



******I would have to check on the origins of the first Sunglow.?

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