Posted by:
mdc
at Wed Jun 22 09:59:18 2005 [ Email Message ] [ Show All Posts by mdc ]
Andy,
Try to work it out like this, sometimes it is easier to understand.
First deal with the anery gene. Each parent in your case is het anery. Remember we are forgetting about them being hypos right now, because that has nothing to do with the anery gene. So in het x het you would get 1/4 anerys, 1/2 het anery, and 1/4 normals. The problem is you can't tell the het anerys from the normals, so they would be 66% het anery.
Now for the hypo gene. Try to think of the hypo gene being het for super hypo and that will help you understand. So breeding hypo to hypo is basically breeding het x het, so you would get 1/4 super hypo, 1/2 hypo, and 1/4 normal. The only difference from the het to het anery breeding above is that you can tell the het animals since hypomelanism is a dominant trait.
So, now that you have done each trait individually just put them together. Say you had 16 babies to make this simple. Of those 16 babies, 1/4 (or 4) should be super hypos. Now of those 4 super hypos, 1/4 (or 1) should be anery, 1/2 (or 2) should be het anery, aka dh ghost, and 1/4 (or 1) will be normal. Then just break them all up like this. However, with this breeding you will have to sell all the hypos (ghosts included) as possible supers. And, you will have to sell all the non anery siblings (hypo and normal)as possible het anery.
Hope this helps,
Matt
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RE: Genetics question for breeding salmon het for anery... - mdc, Wed Jun 22 09:59:18 2005