>Hypo that is het anery plus anery = 50% ghost and ?

If the hypo is caused by a dominant mutant gene like salmon, then the expected babies would be
1/4 normal-looking, heterozygous anerythristic
1/4 anerythristic
1/4 hypo, heterozygous anerythristic
1/4 hypo anerythristic (ghost)

>Super Hypo that is het for anery plus anery = 100% ghost

1/2 hypo, heterozygous anerythristic
1/2 hypo anerythristic (ghost)

>Now Salmon is a form of Hypo so what does a Super Salmon that is het for anery plus anery = ?

1/2 salmon, heterozygous anerythristic
1/2 salmon anerythristic (ghost)

>I understood everything else in this thread

>Hypo Co-dom = half of liter will show if bred to something other than hypo

That is herper pseudogenetics lingo. The standard genetics term is heterozygous hypo, which is a dominant mutant gene. This means that there is a hypo mutant gene paired with a different gene, in this case a normal gene. Whenever a heterozygous individual is mated to an individual with a pair of normal genes, the result is 1/2 with two normal genes and 1/2 heterozygous. This is true for recessive mutant genes like albino and for dominant mutant genes like salmon. Salmon (aka hypo) is a dominant mutant gene because the heterozygous individuals, with a salmon gene paired with a normal gene, have the salmon (hypo) appearance instead of looking normal.

>Super = all of liter will show

More herper pseudogenetics lingo. The standard genetics terminology is homozygous (having a pair of identical genes) for a dominant mutant gene. When an individual that is homozygous for a dominant gene is mated to a homozygous normal individual, then all the babies are heterozygous for that dominant mutant gene and show whatever appearance that mutant causes.

>Anery rec unless bred to another anery will not show at all

When a homozygous anerythristic is bred to a homozygous normal, all the babies are heterozygous anerythristic. Anerythristic is a recessive mutant gene because heterozygous anerythristic snakes look normal.

When a homozygous anerythristic is bred to a heterozygous anerythristic, half the babies are heterozygous anerythristic, and half the babies are homozygous anerythristic (anerythristic).

>so hypo het anery plus anery = a snake that is Homozygous for hypo but hetrozygous for anery = ghost

Sorry, you are off. Ghost is homozygous anerythristic and either homozygous or (usually) heterozygous hypo.

Hypo x normal --> 1/2 hypo (heterozygous hypo), 1/2 normal

het anerythristic x anerythristic --> 1/2 heterozygous anerythristic (look normal), 1/2 anerythristic

As the results combine at random, 1/2 of the hypos are anerythistic, and 1/2 of the hypos are het anerythristic. And 1/2 of the normals (at the hypo locus) are het anerythristic, and 1/2 of the normals (at the hypo locus) are anerythristic. Multiply the fractions, and the final result is
1/4 normal-looking, heterozygous anerythristic
1/4 anerythristic
1/4 hypo, heterozygous anerythristic
1/4 hypo anerythristic (ghost)

>Also what is the difference between a type I and type II anery

Sorry, I do not know how to tell the difference between these two. As I understand it, mating the two together produces normal-looking babies that are heterozygous for both mutant genes.

Hope this helps.

Paul Hollander

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