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Hello i have a pair of 50% het anery boas from the same litter and was wandering if I could breed them together? Also what would I get as far as colors from the litter. If I got a hypo would I get anything from that. Just curious, Thanks Matt

>Hello i have a pair of 50% het anery boas from the same litter and was wandering if I could breed them together? Also what would I get as far as colors from the litter.

You could breed them together if you want. I'm not strongly in favor of the idea, but I wouldn't turn thumbs down either.

First, brother x sister is close inbreeding, which isn't a great idea most of the time.

Second, I assume you want to get anerythristics from them. Statistically, there are four possibilities when a bair of 50% probability for anerythristics are bred:
1) 1/4 of the time, both are normal, with no anerythristic mutant gene in either. Result, all normal babies.

2) 1/4 of the time, the male is normal and the female is heterozygous anerythristic. Result, all normal looking babies.

3) 1/4 of the time, the male is heterozygous anerythristic and the female is normal. Result, all normal looking babies, as in case 2.

4) 1/4 of the time, both are heterozygous anerythristic. Statistical result, 3/4 normal looking babies (66% probability heterozygous anerythristic), 1/4 anerythristic.

As your chance of getting two heterozygous anerythristic boas isn't good, you'd do better to breed these snakes to either an anerythristic or a heterozygous anerythristic to find out whether one or both snakes is actually heterozygous anerythristic.

>If I got a hypo would I get anything from that?

I assume by "hypo" you mean Rich Ihle's salmon boas. Salmon is either a codominant mutant gene or a dominant mutant with variable expressivity. Short answer is salmon x 50% probability heterozygous anerythristic will producue at least some salmon babies.

Paul Hollander

Thanks, so my best bet would probly be to get an anery or a 100% anery from a reputable breeder then. Matt

Your best bet would be to get a pair of anerythristics. Then you could test both male and female of the 66% probability heterozygous anerythristic boas. Other choices, in descending order of preference are as follows:

2) an anerythristic of one sex and a heterozygous anerythristic of the other sex.

3) a pair of heterozygous anerythristics.

4) a single anerythristic of either sex.

5) a single heterozygous anerythristic of either sex.

Which choice you make depends on how much time and money you are willing to spend in the project. The less money spent means the more time needed.

BTW, is there a difference between an anerythristic and a 100% anerythristic?

Paul Hollander