Reptile & Amphibian Forums

Ok lets see who can come up with the right outcome here...
What would I get if I bred the following 2 snakes together?
Striped Butter X Goldust Het Motley

also what about...
Ultramel Motley het Caramel X Golddust het motley

and if your really smart
Striped Butter X Ultramel Motley het Caramel

25% Butter (het. stripe)
25% Golddust (het. stripe)
25% Butter Motley (het. stripe)
25% Golddust Motley (het. stripe)
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0.1 Snow Corn "Hope"
1.0 Ball Python "Wilson" (Castaway)
1. Orange Albino Black Ratsnake "Chunk" (Goonies)
.1 Orange Albino Black Ratsnake "Peaches"
0.0.1 Mexican Black Kingsnake "Onyx"
0.0.1 Black Ratsnake "Molly" (Flogging Molly)

As we say in Missouri, "I ain't goin back to Missouri!"

I haven't followed the market as close as I used to so I'm not really up on the Goldust line. For the last couple of years I have only been focused on my own corn project and my okeetees.
This is what I believe will be the result of your breeding the following: Striped Butter X Goldust Het Motley

All Normals that are 100% het for butter, goldust, and striped as well as 50% possible het for Motley.
Motley and striped are recessive as is butter and I'm assuming that goldust is also. I may be wrong on the goldust as I stated previously. I'm not familiar with the goldust morph. It looks like all the traits/genes you are breeding are recessive and neither parent carries a matching gene.

np
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ontogeny recapitulate phylogeny

Charlie Mike

God knows all, and as man finds parts of that all, god changes those parts of all. Then he laughs at us!!!
(Me)

1.3 Bearded Dragons (Eenie, Meanie, Minie and Moe is the Male

6 baby female Western hognose, 3.5 adults some friend some mine,,,building breeding stock) All Named George
1 Corn snake (bloodred) 0.2 1 MIA In the house I hope (All corns named Ray Guy
1 baby creamcycle 0.1
2 Okeettes I think? 1.1 youngens
ochrocephala oratrix 0.0.1? Adult, and a killer!
ochrocephala auropalliata 0.0.1? Adult
2.0 Dogs, Michigan, Doc
0.2 Cats,, Sassie and Spooky (all black cat)
0.1 Wives, (Long term captive!,, I mean ME!) I call her (BOSS)
1.1 Kids (Paininthearsius takamemonii) J/K great kids
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tom

www.herpzilla.com

These are not hybrids...
The striped butters were acquired in person from Don Soderberg of South Mountain Reptile.
The Golddust was purchased directly from Rich Zuchowski of Serpenco.

25% Striped Motley Goldust
25% Striped Motley Butter
25% Goldust Het Stripe
25% Butter Het Stripe

I'm curious about the answers but I'm eager to learn about this goldust morph. As stated previously, I'm not familiar with it so I don't know what it looks like nor do I know if it is a recessive gene. I based my answer on all the traits being recessive. Neither parent had the same recessive genes, no matchup, no morph. I just used the genetics wizard and input butter, goldust, striped as homozygous recessive traits and motley as hetorozygous recessive trait. Here's what I got for that breeding:

Homozygous butter, Homozygous striped,
x
Homozygous goldust, Het. motley,

50% Het. butter, Het. striped, Het. goldust,
50% Het. butter, Het. striped, Het. goldust, Het. motley,

These are all hets, no homozygous / morph hatchlings. All normals that are hets. That is what I responded but I see that several people are responding different. How is that possible? Is the goldust morph related to butter? I checked on SMR, no info. Same for Kathys site.

I'm not sure what the goldust is but I think I read that a butter x goldust gives you 50% butter and 50% goldust so I assume the goldust is a het ultra het butter. The ulta gene is compatible with amel, so the offspring of the goldust would get ether the ultr or amel gene.

The striped and motley genes are compatible so an offspring that received both would show a combination of the traits. If they don't show the combination it means they only received the striped gene.

Ultramel Caramel...
This animal was purchased from and prodcued by Rich Z.

I mean GOLDDUST not goldust

Ultra is a recently discovered hypo type gene that is non allelic with any of the other hypo verieties. What was found out is that the Ultra gene resides on the same locus on the chromosone string as the Amel gene does. So, when a homozygous Ultra is bred to ANY form of Amel, one parent sends down the ultra and one the amel and both sit in the same locus thus forming a combo type animal. This gene combo was named Ultramel since it is an animal that exhibits both the amel and ultra (hypo) look.

When the caramel gene is added to the mix it ends up being a snake carrying the ultra and amel gene on one locus and the caramel on the other so is a really neat souped up butter. This was named Goldust.

So, in answer to the question given, breeding the aforementioned snakes should result in 50% goldust and 50% butter. Out of those, 50% should be stripe/motley and 50% het stripe. The reason that you would NOT get normals is that the ultra and the amel combine just like two amel genes would combine to make an amel looking animal. So you do end up having compatible gene mixes that will produce non normal results.

Hope this helps some.

thx