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World Morph Count?

sneakyfree Jun 26, 2006 10:35 AM

Anyone out there have any thoughts?
My random guesses:

Yellowbellies: 5,000
Pastels: 5,000
spiders: 3,000
Cinny/Black Pastel: 1,500
albinos: 1,500
Pieds: 1,000
Clown: 400
Genetic Stripe: 100
Lavender Albinos: 20

How far off am I? Where could you find out info, or generate more accurate figures for this?

Thanks!

Replies (12)

JaredHorenstein Jun 26, 2006 11:26 AM

You are so far off on some of these assumptions............

5,000 yellowbellies................I bet there are 5,000 yellowbellies in Africa alone the way they are coming in daily..........

1,000 pieds............I thik Pete may have produced close to a few thousand by now............al by his lonesome.....

Kinda rediculous...........but keep guessing.

sneakyfree Jun 26, 2006 11:30 AM

i'm new to this and was just shooting from the hip...didn't mean to come accross as ignorant as i am (lol)...so what are your numbers like for the morphs i listed?

sneakyfree Jun 26, 2006 11:34 AM

not even trying to speculate the wild count, what i'm interested in are perspective estimates of captive animals...anyone else have some numbers based on any facts? i am just really curious what differing estimates there are out there....

BelgianBeer Jun 26, 2006 11:58 AM

Your numbers are so low it is not even funny. I know of some breeders producing close to those numbers each year.

morphed Jun 26, 2006 01:00 PM

Times your totals by about 10 and you may have a more accurate assumption... Well closer too...
Kim

sneakyfree Jun 26, 2006 01:25 PM

Although I was unable to attend, I heard there was less than a dozen clowns at daytona last year! even fewer lavenders, but hundreds of spiders, pastels, albinos, pieds etc...not thousands of anything.....it made me wonder about what the captive numbers of different morphs ranged...i'll be the first to admit that i have no real idea...just pure speculation that is undoubtedly far from actuality, but so far no one else has posted a list of their own estimates...

kaysie Jun 26, 2006 03:19 PM

What makes it to Daytona is not nearly representative of what is available. Only the major breeders can even afford a table at Daytona, let alone the cost of getting all the animals there from wherever they are.
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1.1.2 Python regius
0.0.1 Eunectes notaeus
0.0.1 Lampropeltis spp.
5.0.0 Ambystoma mexicanum
1.3.0 Triturus karelinii
1.3.0 Taricha granulosa
0.3.0 Ambystoma jeffersonianum
0.0.3 Salamandra salamandra
0.0.1 Tylototriton verrucosus
1.0.0 Grammastola cala
1.0.0 Homo sapiens 'Hottie'

Amazonreptile Jun 26, 2006 04:18 PM

Furthermore, what is at a show and is VISIBLE is simply a fact9or of what is available that week. A small snapshot of time for an entire hatching season.

Also, keep in mind what is visible does not reflect what is under the table or back in the hotel room.
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AMAZON REPTILE CENTER

NAMED BEST REPTILE STORE IN LOS ANGELES

Kingofspades Jun 26, 2006 04:32 PM

5000 pastels?
Everyone and their grandmother is breeding pastels.
They're the most affordable visual morph...

I'd say more like 15,000.
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-Man fears the beast in the Wolf because he does not understand the beast within himself.

sneakyfree Jun 27, 2006 10:22 AM

15,000...so amazing to think that around just a decade ago, the first CB pastels were hatched...and now there are 15,000? Who knows for sure? I wonder if there might be a way to use Daytona as a means of calculating a rough estimate of various CB morph counts? obviously only a fraction make it to display....but if there were only say, a dozen clowns, and 1000 pieds...how does this correlate to the value of each as an investment animal from a scarcity-factor standpoint?
what if someone was able to determine that on average, say only 10% of the world's supply of a morph is present at Daytona? then you just multiplay by a factor of ten to get a rough estimate....but some years, a majority of the the most rare and cutting edge morphs make it to daytona...for example, in '04 there were only a handful of leucistics in existence, a higher percentage of those that were produced made it to Daytona than the more common morphs...
anyone out there have any idea how to more accurately determine the ratio of various morphs? mojave's and spiders have been around a lot shorter than albinos, but do they already outnumber albinos? do pinstripes outnumber albinos already? how long till lessers outnumber albinos?

coldthumb Jun 27, 2006 11:46 PM

Getting a global inventory?..haha wow good luck.

Besides,there is the other side to that elusive equation.The buyers.That number is growing daily,and has been ever since i started researching reptiles online in 2001.

I wonder how many new visitors this forum gets in a week?Let alone the vast number of other forums there are now.This runaway train of a hobby is still accelerating.

Which will make it quite impossible for you to get your data anywhere near to a useful point.

good luck though
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Charles Glaspie

Tanstaafl:
"There ain't no such thing as a free lunch".
An acronym created by my favorite author Robert A. Heinlein.

crazydart Jun 27, 2006 11:48 PM

if you even have a shot at an estimate, you are going to have to figure out a formula to calculate the number produced per year. This will have to keep in mind the breeding potential of males creating hets and those hets creating babies, and the fact that it will take the average female 2-3 years to reproduce. With a formula like that (it would take some work but it could be done) you should be able to figure out how many of each morph there is, assuming each morph started with ONE visual animal. The problem is thats not the case with most the morphs. There are visuals of most of the morphs still WC and imported each year... so it will mess up the figures, BUT you should be able to get an idea of ATLEAST how many there are.

YEAR1(1997) - I have an albino male... year 1 I breed him to 6 normal females, all lay 8 (would use good females for a project like this), produce ALL hets, (1*6)*8=48 hets 50/50 gendar split....
YEAR2 - 24 male hets and 1 homo breed 6 normal females each... all lay 8 eggs... thats (1*6)*8=48 hets, (24*6)*8=1152 poss hets.
YEAR3 - 24 het females are now ready to breed from 1997.... etc...

You get the point.

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