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ARABESQUE gean question

Z_G_Reptiles Jul 27, 2006 09:33 PM

hi, i was trying to find out if the ARABESQUES gean is recesive, co-dom, dom, or what?
thanks for anyone that replies
Zack
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1.1.0 Brazilian Rainbow Boa
1.0.0 Yellow Anaconda
1.1.0 Suriname Red Tail Boa
1.0.0 Guyana Red Tail Boa
0.1.0 Red Blood Python
0.1.0 Jungle Carpet Python (VPI Bloodline)
1.0.0 Cat

Replies (13)

PanamaRed Jul 27, 2006 10:04 PM

It is a co-dominant possibly dominant trait. I don't think anyone has proven a super at this point.
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Ed Lilley, www.constrictorsnw.com
www.reptileinsider.com

Z_G_Reptiles Jul 27, 2006 10:43 PM

so if you breed it with a normal you'll get some ARABESQUES and then some het? just tyring to understand the genetics
thanks
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1.1.0 Brazilian Rainbow Boa
1.0.0 Yellow Anaconda
1.1.0 Suriname Red Tail Boa
1.0.0 Guyana Red Tail Boa
0.1.0 Red Blood Python
0.1.0 Jungle Carpet Python (VPI Bloodline)
1.0.0 Cat

NUCCIZ_BOAS Jul 27, 2006 11:22 PM

If you bred an Arabesque to a normal, in theory, the litter would be 50% arabesques, and 50% normal.

Z_G_Reptiles Jul 27, 2006 11:24 PM

ok thanks, i'm thinking of breeding a sunglow to a arabesque het for albino
anyone know what i'd get?
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1.1.0 Brazilian Rainbow Boa
1.0.0 Yellow Anaconda
1.1.0 Suriname Red Tail Boa
1.0.0 Guyana Red Tail Boa
0.1.0 Red Blood Python
0.1.0 Jungle Carpet Python (VPI Bloodline)
1.0.0 Cat

BoidaeAddiction Jul 27, 2006 11:56 PM

You would get a mix, some, maybe all of these depending on how independent assortment takes place: Sunglows, Arabesque Sunglows, Arabesque Albinos, Hypo Arabesques 66% het albino, Normal Arabesques 66% het for albino, Normals 66% het albino, 66% DH Sunglow. Arabesques do have a super, or dominant form. Breeding an arabesque to an arabesque will theoretically create 25% of the litter as super arabesques; similar to when you breed a heterzygous animal to a het. I "know" that the super exists, in fact, killer boas has one and perhaps others people have these as well, but I don't know that it has yet been put to the test and if a whole litter of arabesques was produced from the dominant form. This is the same boat the "black patternless" is in, MotleyXMotley result in the black patternless or dominant motley, however, it has not yet been bred and proven, though it most definetly the super/dominant form. Hope my long post didn't strain your eyes, Trey Schneller, Schneller Reptiles

Rainshadow Jul 28, 2006 12:42 AM

That your sunglow is expressing the "hypo" trait in its heterozygous form,(ie;not a "super".)and also assuming that the Arabesque,het albino is expressing the Arab trait in its het form,the statistical breakdown should look something like this:12.5% Het. albino,
12.5% Het. albino, Het. hypo,(double het sunglow)
12.5% Het. albino, Het. arabesque,
12.5% Het. albino, Het. arabesque, Het. hypo,(triple het Arab sunglow)
12.5% Homozygous albino,
12.5% Homozygous albino, Het. hypo,(sunglow)
12.5% Homozygous albino, Het. arabesque,
12.5% Homozygous albino, Het. arabesque, Het. hypo,(Arab sunglow)
There are no "poss. hets" because the sunglow is expressing albinism in its homozygous form,anytime one parent is homo albino,all offspring are hets,even if the other parent isn't carrying the gene at all. hope this helps...

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Rainshadow Jul 28, 2006 12:52 AM

That last part should say: all offspring are either albinos,or they are hets,(if the other parent isn't carrying the gene,none will be albinos.)breeding an albino removes the "possible" from the equasion.
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bthacker Jul 28, 2006 01:34 AM

I thought Arabesque's where co-dominant animals. How could they be het. for Arabesque?

bthacker Jul 28, 2006 01:38 AM

I had to look at that over again...."het" meaning co....right? One more beer and I am off to bed....

Rainshadow Jul 28, 2006 02:24 AM

Look at things a bit differently than what is often considered "marketplace standard",(I guess,is a good way to put it...*lol*)I don't believe the Arab trait "is" co-dominant,I believe it will prove to be a form of just plain old dominant,like the "hypo" or salmon trait....if you breed an animal thought to be some form of dominant,and you consistantly get roughly a 50/50 split,expressive & "normals"...that trait carrier is "heterozygous" for that trait,if you get roughly 100%,(or there-abouts) that's your "super",(or in plain old genetic terms:"homozygous" )the Arabs I've seen pictures of,that are thought to be possible "supers",are not phenotypically different from the originally described examples,they could best be described as "exagerated" in expression,just like "super hypos" are often exagerated in appearence from the hets in a given litter containing both,but ultimately they need to be bred to ascertain their true status,whereas a true co-dominant mutation produces a homozygous form that is distinct from both the hets,and the normals.(so most people look at a het hypo,and say "co-dom",I contend that the trait consistantly proves there's no such thing.) I might need one of those beers?
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BoidaeAddiction Jul 29, 2006 01:02 PM

I was thinking you wanted to breed a DH sunglow to a arabesque het albino, listen to Tim, he catches all my mistakes, lol. Should have re-read your post before I started to give advice

Rainshadow Jul 29, 2006 01:10 PM

Glad you posted,thought I'd pissed you off Sorry I missed you last time I was in the neighborhood,maybe next time? (save me a cold one!)
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BoidaeAddiction Jul 30, 2006 07:24 PM

Hey man, its cool, I can be corrected without crying like a baby, or trying to prove how I was right. Honest mistake. You know that there is always a case of brews with your name on them; I keep them stocked and on standby just in case you drop by. Come up on Monday if you get a chance; still wondering if you were interested in the Het T positive. Peace and hairgrease, Trey.

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