>1.0 Albino
0.1 Normal
1.0 Anery (66% Het Snow)
0.1 Hypo (66% Het Snow)
The Anery (66% Het Snow) has a 66% chance of being heterozygous albino and a 33% chance of not being het for anything.
The Hypo (66% Het Snow) actually has the following probabilities:
4/9 heterozygous albino, heterozygous anerythristic
2/9 heterozygous albino
2/9 heterozygous anerythristic
1/9 not heterozygous for either albino or anerythristic
You can make 4 matings with these snakes:
1. albino x normal --> all normal-looking babies, heterozygous albino
2. albino x hypo. This is a test cross to see if the hypo is heterozygous albino. No anerythristics would be expected to come out in the babies, so I will skip that mutant. There are 2 possible answers.
albino x hypo, heterozygous albino -->
1/4 hypo albino (sunglow)
1/4 hypo, heterozygous albino
1/4 albino
1/4 normal looking, heterozygous albino
albino x hypo (not het for albino) -->
1/2 hypo, heterozygous albino
1/2 normal-looking, heterozygous albino
3. anerythristic x normal --> all babies look normal and are heterozygous anerythristic.
4. anerythristic x hypo. This is a test cross for whether the hypo is het anerythristic. There are two possibilities:
anerythristic x hypo, heterozygous anerythristic -->
1/4 hypo anerythristic (moonglow?)
1/4 hypo, heterozygous anerythristic
1/4 anerythristic
1/4 normal looking, heterozygous anerythristic
anerythristic x hypo (not het for anerythristic) -->
1/2 hypo, heterozygous anerythristic
1/2 normal-looking, heterozygous anerythristic
If any albinos or sunglows come out of this mating, then both the anerythristic and the hypo are also het albino. That would be a pleasent surprise, and the nonalbino babies could be rated as 66% probability het albino, too.
The first year I would mate anerythristic x hypo and albino x normal. Because you might get lucky and prove both the anerythristic and hypo are heterozygous albino. The second year I would mate albino x hypo and anerythristic x normal.
On the other hand, I'm not up on prices. It might make better economic sense to try for sunglows first.
You could put both males with both females, but that wouldn't prove out any of the 66% probability hets.
Hope this helps.
Paul Hollander