Reptile & Amphibian Forums

hello.
im looking to get a female to breed my anery w/. but really have not figured out the pairings out yet.

so i figured i would ask.

What would be the "best" mate to produce the most desirable clutch or snows?

thanks

Assuming your male proves to be Het for Snow, you could pair him with an Albino 100% Het for Anery and you should get
25% Snows
25% Albinos 100% Het for Anery
25% Anery's 100% Het for Albino
25% Normals 100% DH for Snow
Best of luck!
Kevin Blumenthal

This anerythristic will produce snows only if he is heterozygous albino (aka het for snow). If he is not, then he can't sire snows.

Assuming that he is heterozygous albino, mating him to the following females will produce snows. I've listed the four females in order of desirability, with the most desirable mating first.

1. snow -->
1/2 snow
1/2 anerythristic, heterozygous albino

2. albino, heterozygous anerythristic -->
1/4 snow
1/4 albino, heterozygous anerythristic
1/4 anerythristic, heterozygous albino
1/4 normal looking, heterozygous albino, heterozygous anerythristic

3. anerythristic, heterozygous albino -->
1/4 snow
2/4 anerythristic, heterozygous albino
1/4 anerythristic
(The anerythristics could be called 66% probability heterozygous albino.)

4. heterozygous albino, heterozygous anerythristic -->
1/8 snow
3/8 anerythristic, 66% probability heterozygous albino
1/8 albino, heterozygous anerythristic
3/8 normal looking, heterozygous anerythristic, 66% probability heterozygous albino

Matings 2 and 3 could be expected to produce the same fraction of snows. However, the anerythristic male is only a possible het for snow, if I'm reading this right. Seven normal babies without any snows or albinos from mating 2 means that the odds are 99% that he is not heterozygous albino. Mating 3 must produce 17 normal babies and no snows to get 99% odds.

Good luck.

Paul Hollander