Reptile & Amphibian Forums

What is the ratio odds of the offspring when breeding a Mojave to a Pastel? Is it like breeding a het to het? say on 4 eggs, hypothetically should there be:

1 Mojave
1 Pastel
1 Pastel Mojave
1 Normal

Thanks in advance for any help.

It IS breeding a het to a het, remembering this will make it a lot less confusing to figure out crosses like this.

The mojave phenotype is heterozygous for the mojave gene and the pastel phenotype is heterozygous for the pastel gene. The inheritance odds are the same for mojave X pastel, het albino X het albino, and het axanthic X het clown. In each case the parents have unmatched versions of the genes for the mutations mentioned (the definition of heterozygous) so each parent has a 50% chance of passing the mutant version of each gene to each offspring.

For each egg the odds are:

25% chance of getting the mutant version from the father only
25% chance of getting the mutant version from the mother only
25% chance of getting the mutant version from both
25% chance of getting normal versions from both

The only differences between the three scenarios are:

1. you can see the mojave and pastel hets (unlike the albino, axanthic, or probably clown)
2. with albino het X albino het you can see the babies that get albino from both (unlike the axanthic het X clown het example where you have normal looking 25% chance double hets).

Thanks Randy, thats kinda what I figured but wanted to ask to be sure. I'm hoping to get at least 1 Pastel Mojave out of the clutch of 7 eggs. Odds are pretty good, but nothings for sure in this field.

Steve

Each egg that hatches to produce a single baby from this pair has a 25% chance of being pastel mojave. The cumulative odds of getting at least one out of 7 such hatchings is:

1 - (.75)^7 = 86.7%