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I've got a few questions on 'supers' and hets.

If a 'super' ghost were bred to an albino het for anery, would all of the babies be ghosts, or half?

What about a 'super' hypo to a non-hypo?

If a boa that is het for albino or anery, is bred to a regular
boa, then 50% of their offspring would carry that het gene, or
would it be 25%?

Thanks

If you bred a super ghost to an albino het anery half the clutch would be ghosts het albino. the other would be triple hets.

a super to non hypo would yield all hypo babies.

a het bred to a non het makes 50% het babies. half the clutch should be het for the recessive trait.

het to het would yield 1/4 of recessive trait being that they are het for the same trait. the rest would be "normals" 66% het for the trait.

think that covers most of it.
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It's almost like learning my abc's all over again.

first question:

"If a 'super' ghost were bred to an albino het for anery, would all of the babies be ghosts, or half?"

--Half of the babies would be ghosts, and they would all be het albino.

second question:

"What about a 'super' hypo to a non-hypo?"

--All babies would be hypos. (but no super hypo babies)

third question:

"If a boa that is het for albino or anery, is bred to a regular
boa, then 50% of their offspring would carry that het gene, or
would it be 25%? "

--The babies would be 50% het for albino or anery. (to get 25% hets you would have to breed a 50% het to a normal.)

Hope that helps!
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www.bryansboas.com

>>"If a boa that is het for albino or anery, is bred to a regular
boa, then 50% of their offspring would carry that het gene, or
would it be 25%? "
Yes 50% should carry the single gene for that Genetic mutation. Making those gene carriers Heterozygous(Hets)

>>--The babies would be 50% het for albino or anery. (to get 25% hets you would have to breed a 50% het to a normal.)

Not to be picky or mean but this statement really doesn't hold up. With a Recessive trait.50% possible Hets either prove out to be het or don't prove out to be het.There is no way to end up with 25% hets. They will either be heterozygous or they will not be heterozygous.
Hope this makes sense.
. . . . Lar M
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Boas By Klevitz
Boas By Klevitz

Understood, but the point is if a 50% het were bred prior to being proven out and to a normal or any other that was not het for the same recessive trait then you would have 25% hets.

Yes a x% het is either a het or it is not, but until proven it's going to stay a x% het.

>>>>"If a boa that is het for albino or anery, is bred to a regular
>>boa, then 50% of their offspring would carry that het gene, or
>>would it be 25%? "
>>Yes 50% should carry the single gene for that Genetic mutation. Making those gene carriers Heterozygous(Hets)
>>
>>>>--The babies would be 50% het for albino or anery. (to get 25% hets you would have to breed a 50% het to a normal.)
>>
>>Not to be picky or mean but this statement really doesn't hold up. With a Recessive trait.50% possible Hets either prove out to be het or don't prove out to be het.There is no way to end up with 25% hets. They will either be heterozygous or they will not be heterozygous.
>>Hope this makes sense.
>> . . . . Lar M
>>-----
>>Boas By Klevitz
>> Boas By Klevitz
>>
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

And duh, the more responsible thing to do would be to prove out the het status FIRST, but not everyone has all the genetics available.
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

Dave ,I was hoping you would add your increased Mathmatics abilities to this discussion.
I understand the premise of the 50% odds turns into 25% odds statement.
I just don't asgree that it will ever apply. I supposed one has to look at it completely as a role of the dice (which it is)to accept 25% odds or 25% chance.
My point is you have the 50% chance that it is het. If it proves to be het. Then once again those offspring will be 50% Hets.If it doesn't prove there will not be 50% hets, there will be 25% hets.
There will never be a time when 25% of the offspring are Hets. That was my point. Am I making any sense at all ?,LOL
. . . . . Lar M
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Boas By Klevitz
Boas By Klevitz

oops left out one crucial word in a crucial sentence

>>Then once again those offspring will be 50% Hets.If it doesn't prove there will not be 50% hets, there will be 25% hets.

I ment to say: Then once again those offspring will be 50% Hets.If it doesn't prove there will not be 50% hets, there will not be 25% hets.

. . . . . Lar M
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Boas By Klevitz
Boas By Klevitz

Yes you are making sense but where you are getting off the path is the 25% refers to the statistical probability of a single baby (in a large enough population) being a het, not the percent that will actually be het in a smaller population.

For example, if you had two 50% het females and it was a perfect world, one would be het and one would not. In that same perfect world both sisters were bred by one or more normal males and each had 10 babies. The one that was not het at all would have 10 non-het babies. The female that was het would have 5 het babies and 5 non het babies. Put all 20 in one pile and 1/4 would be hets while 3/4 would not. Remember, at this time none are proven. Even if all were kept seperate or somehow ID'd so you knew exactly which was which, until one het proved, either one of the mom's or one of the babies, the babies as a group would each have a 25% chance of being a het. Obviously once one proves out than you can divide up the group in half to get non hets and 50% ones.

And YES, there would not be one litter where 1/4 of the babies would be expected to be hets. (of course the odds gods get final say in actual outcomes)
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

Dave This is a perfect analogy to explain a percentage of probability for a trait. I agree this is perfect math and that probability of receiving the trait has now been cut from 50% to 25%. I obviously was looking at the original statement from a different or wrong perspective.
For example the way I like to explain 66% Hets is as such.
If you Breed two Hets together and they produce 16 babies. Of those 16 babies 4 will be Homozygous. Of the 75% Remaining or 12 babies , of these (66% ) or 2 out of 3 will receive the trait This means there are 8 hets and 4 normal.
. . . . . Lar M
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Boas By Klevitz
Boas By Klevitz

Lar

I like to use the punnet square approach to describe the 66% het number.

In a het to het albino breeding the punnet square will define four equal size groups of babies...

aa - These babies will get two albino genes, one from mom and one from dad.

aA - These babies will get an albino gene from mom and a normal gene from dad.

Aa - These babies will get a normal gene from mom and an albino gene from dad.

AA - These babies will get two normal genes, one from mom and one from dad.

The homozygous albino group are obvious (duh) and easily seperated from the overall group Leaving 3 groups left of which 2 out of 3 (2/3) groups are het. Since you can't visually tell them apart all three groups get lumped together and 2/3 probability on any one individual.

I know - you already understand it, just talking you through my thought process and explanation I use to educate those that do not already understand it.

And of course the always important disclaimer - individual litters will vary.
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats

That's definitely a solid way to explain the 66% possibility and at the same time help a person understand a Punett square more thoroughly Dave.
Obviously you are very Analytical I believe would be an appropriate term.,LOL
. . . . . Lar M
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Boas By Klevitz
Boas By Klevitz

Thanks, really, I just get into the whole genetics and numbers and probabalities. I even figured out how to calculate a specific outcome from any multi morph pairing in my head!!! Actually quite simple when you break it down into simple fractions.

When I was starting I even wrote my own punnet square calculator into a spreadsheet, can handle four seperate morphs recessive and dominant. Still have it but rarely ever use it.
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Thanks,

Dave Colling

www.rainbows-r-us-reptiles.com

0.1 Wife (WC and still very fiesty)
0.2 kids (CBB, a big part of our selective breeding program)

LOL, to many snakes to list, last count:
26.49 BRB
20.21 BCI
And those are only the breeders

lots.lots.lots feeder mice and rats