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Questions on leucistic balls

AgentJones Dec 17, 2008 05:26 AM

ok, so i know that there are several ways to make a leucistic ball. Mojave x Mojave, Fire x Fire, Lesser x Lesser, Mojave x Lesser, etc. And i know that since all of these examples--since leucistic is a codominant trait--would essentially be "het" leucistic you get a mix of leucistic, and the component morphs with some normals right? So what i'm not clear on is what happens if you were to breed leucistic x leucistic? would you get 100% leucistic offspring? Some leucistic/some component morphs from the parents' parents? or some other combination. I'm not too good at genetics once you get past simple dominant/recessive traits.

Replies (7)

MATTI1919 Dec 17, 2008 06:02 AM

No,depends on the leucist, take for example:

Super lesser: LL

LL x LL --> 100% LL

MojaveLesser

M. = mojave
L. = lesser

MmLl = leucist (has both codom. genes)

MmLl x MmLl

6.25% WT
12.5% Het. lesserc,
6.25% Homozygous lesserc,
12.5% Het. mojavec,
25% Het. mojavec, Het. lesserc,
12.5% Het. mojavec, Homozygous lesserc,
6.25% Homozygous mojavec,
12.5% Homozygous mojavec, Het. lesserc,
6.25% Homozygous mojavec, Homozygous lesserc,

jayefbe Dec 17, 2008 07:14 AM

Actually, that's incorrect. Mojaves and Lessers, while not being the same gene/morph, are found on the same locus. Which means that a Mojave Lesser x Mojave Lesser will throw out all leucistics because each parent is passing on either a mojave or a lesser gene to its offspring. Of course, a quarter of the offspring will be the super mojave grey-headed leucistics. It's a little confusing because they are different morphs, but a leucistic is homozygous for a mutant allele even though it has two different genes. They should be treated the same way as a super pastel, even though your intuition will lead you to believe that's wrong.

AgentJones Dec 17, 2008 12:49 PM

Man thats really confusing. What if you have a Mojavelesser x Leuc from two lessers/two mojaves?

It remains simple if you stick with two [Mojave x Mojave]s or two [lesser x lesser]s right?

Paul Hollander Dec 17, 2008 03:23 PM

Man thats really confusing. What if you have a Mojavelesser x Leuc from two lessers/two mojaves?

It remains simple if you stick with two [Mojave x Mojave]s or two [lesser x lesser]s right?

Here's how to handle a mating of a snake with a mojave mutant paired with a lesser mutant gene and a snake with two mojave mutant genes:

1. Identify the two genes in each parent's gene pair.
M1 = one of the male's two genes
M2 = the male's other gene.
F1 = one of the female's two genes
F2 = the female's other gene.
The mating can be represented as M1M2 X F1F2

2. Use the FOIL technique, which is a variation of the Punnett square. FOIL is the initials of First, Inner, Outer, Last. These refer to gene positions in M1M2 X F1F2.
F for first = M1F1
I for inner = M2F1
O for outer = M1F2
L for last = M2F2
And there are the four gene pairs found in the babies.

For a male leucistic with a gene pair made of the mojave and lesser mutant genes mated to a female leucistic with two mojave mutant genes:
M1 = mojave
M2 = lesser
F1 = mojave
F2 = mojave

F for first = M1F1 = mojave mojave = leucistic
I for inner = M2F1 = lesser mojave = leucistic
O for outer = M1F2 = mojave mojave = leucistic
L for last = M2F2 = lesser mojave = leucistic

As there are four combinations [two leucistics (mojave mojave) and two leucistics (lesser mojave)], the results can be reduced to
1/2 leucistic (mojave mojave)
1/2 leucistic (lesser mojave)

In the same way we get the following result from a leucistic (lesser mojave) x leucistic (lesser lesser):
1/2 leucistic (lesser lesser)
1/2 leucistic (mojave lesser)

This same technique works for any problem involving one gene pair. Problems involving two or more gene pairs are a little more complicated.

Paul Hollander

Paul Hollander Dec 17, 2008 02:50 PM

>but a leucistic is homozygous for a mutant allele even though it has two different genes.

I agreed with the above post except for this part.

Definitions:
Homozygous -- the two genes in a gene pair are the same.
Heterozygous -- the two genes in a gene pair are not the same.
(By these definitions, every gene pair is either homozygous or heterozygous.)

A mojave mutant gene is not the same as a lesser mutant gene. So a leucistic with a gene pair made up of a mojave and a lesser platinum is heterozygous, not homozygous.

Paul Hollander

jokerfish Dec 17, 2008 03:37 PM

Why not try a mojave lesser, to a platty x russo!

lots of variations of leucy!
-----
0.1 Pied
0.2 possible het pied
1.0 Albino
0.1 Albino het female
1.0 Spider
1.0 cinnamon
1.1 Pastel
1.0 Het genetic stripes
0.17 normal females

jayefbe Dec 19, 2008 02:16 AM

If you want to get really technical then, yes. What I meant by saying homozygous was that it would have no normal alleles and only mutant alleles at the BEL-locus. It just makes it a little easier to think about it as homozygous for the trait, when technically it is a het.

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