Man thats really confusing. What if you have a Mojavelesser x Leuc from two lessers/two mojaves?
It remains simple if you stick with two [Mojave x Mojave]s or two [lesser x lesser]s right?
Here's how to handle a mating of a snake with a mojave mutant paired with a lesser mutant gene and a snake with two mojave mutant genes:
1. Identify the two genes in each parent's gene pair.
M1 = one of the male's two genes
M2 = the male's other gene.
F1 = one of the female's two genes
F2 = the female's other gene.
The mating can be represented as M1M2 X F1F2
2. Use the FOIL technique, which is a variation of the Punnett square. FOIL is the initials of First, Inner, Outer, Last. These refer to gene positions in M1M2 X F1F2.
F for first = M1F1
I for inner = M2F1
O for outer = M1F2
L for last = M2F2
And there are the four gene pairs found in the babies.
For a male leucistic with a gene pair made of the mojave and lesser mutant genes mated to a female leucistic with two mojave mutant genes:
M1 = mojave
M2 = lesser
F1 = mojave
F2 = mojave
F for first = M1F1 = mojave mojave = leucistic
I for inner = M2F1 = lesser mojave = leucistic
O for outer = M1F2 = mojave mojave = leucistic
L for last = M2F2 = lesser mojave = leucistic
As there are four combinations [two leucistics (mojave mojave) and two leucistics (lesser mojave)], the results can be reduced to
1/2 leucistic (mojave mojave)
1/2 leucistic (lesser mojave)
In the same way we get the following result from a leucistic (lesser mojave) x leucistic (lesser lesser):
1/2 leucistic (lesser lesser)
1/2 leucistic (mojave lesser)
This same technique works for any problem involving one gene pair. Problems involving two or more gene pairs are a little more complicated.
Paul Hollander