Reptile & Amphibian Forums

I am a little confused. I thought if a leo was Het for "X" it meant it carried the gene for "X" but did not show the visible signs. I dont understand what it means then when someone advertises a leo as 65% Het for "X" or 50% or 75% versus 100% Het for "X" I thought if its Het its 100% Het. How are these percentages come up with and what does that mean as far as useing these for breeding.

100% Het for RAPTOR, 65% Het for Temper Albino, 50% Het for Blizzard.

100% het x non het = 50% het until proven by breeding

50% het x 50% het = 66% het until proven by breeding

100% het x 50% het = 75% het until proven by breeding

Ok so the % is based on the parantage. So if I start out with a male and female both 100% het for "X" breed them and keep breeding the best looking offspring to themselves or back to the parents the offspring will always continue to be 100% het for "X"? As long as you dont introduce any normals or lower % to the eqution then you will always have 100%?

Here's another way to view it:

100% het bred to a normal= all babies have a 50/50 chance of being hets. So they're all 50% hets.

100% het bred to a 50% het or 66% het= If you get the colour morph you're aiming for then the 50% het is now a 100% het becuase it proved out. So the normal babies are going to have a 66% possibility of carrying the gene. So now you're at 66% hets.

100% het bred to 100% het will give you same results as 100% x 50% or 100% x 66%. The only difference will be that you'll get a more even number of normals and visual going by theory.

Then a visual morph bred to a normal= All babies will be 100% hets.

Co-dom and Dominant genes work a little different.
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Phil Red Hernandez-

It's easier to understand once you understand how a punnet square works.

Let's let :

A = "Normal" gene

and

a = albino gene

by breeding [albino (aa) X "Normal" (AA] you will have babies with the following genotype : Aa ....all babies will be 100% het for albino because that is the only possible genotype they can have (if the "normal isn't het for anything).

Now, when you breed 2 of those 100% het fot albino babies together ["Normal" het albino (Aa) X "Normal" het for albino(Aa)] , you have the opportunity to produce babies with different genotypes.
Here's the possibilities from a punnet square:

AA = "Normal" gecko het for nothing
Aa = "Normal" gecko het for albino
Aa = "Normal" gecko het for albino
aa = albino gecko

As you can see, the [Aa] genotpye shows up twice in the possible genotypes produced by the punnet square. So, you are twice as likely to produce a [Aa] genotype as you would a completely normal genotype[AA]. So if you produced a normal looking gecko, it is more likely to be het for albino than completely normal, but there is no way of being sure if it is or not......therefore we take the percentage probability that is has for being het.....in this case we use 2/3 and then we label the normal looking babies as 66% het for albino. Only future breeding will either confirm or dismiss that.

Someone please check everything I've written for errors, I wrote this kinda fast . Thanks.
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1.0.0 Lampropeltis getula holbrooki
0.1.0 Lampropeltis getula californae
0.0.1 Lampropeltis getula nigra
1.0.0 Lampropeltis mexicana thayeri
2.3.0 Eublapharis macularius macularius
0.0.2 Rhacodactylus ciliatus
0.1.0 Gerrhosaurus major major

Ok I think I understand now. Its just saying that if its 75% het for "X" then it has a 75% chance it carrys the gene and therefore a 25% chance it does not.

So once you have bread that leo and it does produce albinos or whatever "X" is het for then it automaticaly changes to 100% het?

Its just an advertisement as to the possibility it carrys the gene for "X".