I assume you are talking about a heterozygous co-dom. A super pastel and a pastel have the same co-dominant mutation so technically could both be called co-doms but a super pastel is homozygous for that mutation and the pastel is heterozygous for the mutation.
I've had the opposite of what you are asking happen. Loaned out a normal female to a pastel (the heterozygous version) and hatched 5 for 5 normals. Same odds - 0.5^x where x is the number of eggs. In my case it was a 1 in 32 chance of hatching 5 normals and would also have been a 1 in 32 chance of hatching 5 pastels. Wouldn't make a difference how many different clutches they are in, it's the total number of eggs that count. 10 in a row would be 1 in 1,024 odds either way and 20 in a row 1 in 1,048,576. If you hatched 20 for 20 pinstripes from pinstripe X normal I would say you have yourself a homozygous pinstripe. Of course pinstripe is now known to be a dominant mutation type and not co-dominant but that’s beside the point, it’s the genotype het vs. homozygous that we are proving here.