Reptile & Amphibian Forums

if i breed my albino to 100% yellow ghost will i produce all hets or will i get visual hets

Each egg will be 100% Het Albino, and have a 50% Chance of being het for Yellow Ghost as well.

No visual morphs.
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Got Balls?
Josh Molone

ok, but according to the punnett that doesnt make sense to me.
Let's say my albino reps aa and my het yellow ghost reps Ng

N g

a Na ag

a Na ag

???
help me understand this!

You actually answered your own question with that punnet square. The "Na" would be Normals, het albino. The other 50% of the clutch (ga) would be het for ghost, AND het for albino. That's why they're ALL 100% het for albino, and the rest of the clutch has a 50% chance of being het ghost.

ok but that still doesnt seem right to me. if the babies are ga where in there is a dominate gene to cover up any visual recessive genes. to me that says that there will be visual morphs. to me thats like saying an albino and a het albino dont throw any albinos just all hets.. please clarify cause I understand what your saying I'm just not seeing it to be true i guess

i just dont see why it wouldnt throw visuals? if you can clarify that then ill be set by the way thanks guys

You are not proposing breeding an Albino to a Het Albino. You asked about breeding and Albino to a Het Ghost, these are 2 seperate color morphs. If your Het Ghost was also Het Albino, then you would have the chance of producing and Albino from the pairing. Hope this helps

ok but where in the pairing, ga, is there a dominate trait that prevents it from being visual offspring what causes no visual morph that still hasnt been answered. that is my question

Dominance and recessiveness are relative to the gene pairs you are talking about. We generally classify genes as "Dominant" or "Recessive" *relative* to the Normal trait.

Albinos are "simple recessive" which means it is a single gene trait that is recessive to the Normal trait. An animal with one copy of a Normal gene and one copy of an Albino gene will look like a Normal because the Albino gene is recessive.

This is courtesy of http://www.geneticswizard.com
Basic Genetics Definitions
Allele - either of the two paired genes affecting an inherited trait (one from the father, one from the mother).

Codominant - an allele that causes the homozygous form to look different than wild type and the heterozygous form to have traits of both. (All three look different from each other.)

Dominant - an allele that causes the homozygous form and the heterozygous form to look the same as each other, but different than wild type.

Recessive - an allele that affects a animal's appearance if it's present in the homozygous state only.† An animal that's heterozygous for a mutant, recessive gene looks wild type, but that gene can be passed on to offspring.

Heterozygous - having two different alleles for a genetic trait.

Homozygous - having identical alleles for a genetic trait.

Wild Type - the way an animal looks with the greatest frequency in a wild population ("normal".

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Lincoln, NE
Ball Pythons - 0.1 Pastel, 1.0 Pastel het Pied, 0.1 Pied, 0.1 Cinn, 1.0 Black Pewter, 1.0 Woma (hidden gene?), 0.1 Yellowbelly
2.1 Normals
Kingsnakes - 1.0 L. m. thayeri, 0.1 L. m. thayeri X L. alterna, 1.0 L. g. californiae
Other - 0.1 Whitesided P. catenifer sayi, 1.0 H. nascicus, ?.? Chrysemys picta, 0.1 crazy cat, 1.0 husband

It's not ga. It's GgAa...you are using shorthand.
This is how it should look

Parent 1 aaGG
Parent 2 AAGg

---------------------aG--------aG--------aG--------aG
AG-------------AaGG---AaGG---AaGG---AaGG
Ag--------------AaGg----AaGg----AaGg----AaGg
AG-------------AaGG---AaGG---AaGG---AaGG
Ag--------------AaGg----AaGg----AaGg----AaGg

AaGG=50%
AaGg=50%

I hope that helps a bit.

Thank you. I was going to do it, but I have had the "punnet square argument" too many times. Best of luck!
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Lincoln, NE
Ball Pythons - 0.1 Pastel, 1.0 Pastel het Pied, 0.1 Pied, 0.1 Cinn, 1.0 Black Pewter, 1.0 Woma (hidden gene?), 0.1 Yellowbelly
2.1 Normals
Kingsnakes - 1.0 L. m. thayeri, 0.1 L. m. thayeri X L. alterna, 1.0 L. g. californiae
Other - 0.1 Whitesided P. catenifer sayi, 1.0 H. nascicus, ?.? Chrysemys picta, 0.1 crazy cat, 1.0 husband

That helps and answers my question thank you very much

If you got it, Ten Points! Not making fun, seriously. Genetics is one of those concepts you don't get, don't get, don't get and then suddenly you get it! Best of luck in your breeding. I love Albinos
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Lincoln, NE
Ball Pythons - 0.1 Pastel, 1.0 Pastel het Pied, 0.1 Pied, 0.1 Cinn, 1.0 Black Pewter, 1.0 Woma (hidden gene?), 0.1 Yellowbelly
2.1 Normals
Kingsnakes - 1.0 L. m. thayeri, 0.1 L. m. thayeri X L. alterna, 1.0 L. g. californiae
Other - 0.1 Whitesided P. catenifer sayi, 1.0 H. nascicus, ?.? Chrysemys picta, 0.1 crazy cat, 1.0 husband

they are both recessive, perhaps you should bone up on genetics before attempting breeding. its always good to have a good base to start from
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www.bamreptiles.webs.com
www.facebook.com/bamreptiles

You are using a four cell square to determine the potential outcomes of two separate traits. A four cell square is used to determine the potential outcomes of one trait. Each side of the square represents one parent and the number of cells is determined by the number of traits you are trying to predict. In the case of two traits, the square has sixteen cells. I hope I am understanding your question right and that this is helpful.

Rob

albino x het ghost = normals 100% het albino and 50% poss het ghost......

aka....$60 a pair ball pythons.....

......get a different partner for each...amels are 200 and up, ghosts are 100 and up....

nuff said....

.
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........JY

aaGG is the correct genotype notation for consideration of your albino male for this particular breeding.
AAGg is the genotype notation of your het ghost for this breeding.
You will notice that I have included the wild type of the other parents mutant gene of interest in this breeding because it also needs to be considered in what gamates are available from each parent.
Here are the gamate possibilities for the albino male: aG
Here are the gamate possiblities for your het ghost: AG or Ag
You set up your punnett square according to the gamate possiblilities (not just what the parents are or number of traits ect) for the genes involved in the breeding, thus your punnet square is simply a 1x2 with the following results in the 2 squares: AaGG and AaGg
AaGG is a het albino with no ghost genes
AaGg is a het both albino and het for ghost
since both possiblities will look normal and you can't "really" tell them apart you would say that all the babies are 100% het albino and have a 50% possible chance of also being het for ghost, or aka 100% het albino,50% possible het ghost.
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Jeff Benfer
gartersnakemorph.com

In order for simple recessives to show themselves (homozygous) BOTH sides of the allele must have the desired gene. If not you will get the wild type expression of the particular animal. For example:

Breed albino to a genetic stripe. Both animals give off nothing but homozygous genes, but they won't line up on a single allele together. Therefore you hatch all normal looking offspring but they all WILL carry both genes hidden by the normal colors.
By using the the theory you describe, when breeding an albino x genetic stripe the ENTIRE clutch would be albino genetic stripes. And we all know it is not that easy to produce a double homozygous animal.

If you expand your square to how Mr. Benfer described it should help figure out why normals will appear in your clutch.

Scott