>What sort of ratio would you expect with a 66% x 66% pairing, etc? Is there a simple rule of thumb to follow without needing a degree in genetic biology?
Simple rule of thumb: mate a 66% or 50% probability heterozygous albino to either an albino or a heterozygous albino (AKA 100% het), first. That way, you will find out if the 66% or 50% is a heterozygous albino or a normal.
Here's the reasoning:
You get a male and a female, and both are 66% probability heterozygous albino. So you could have purchased either a heterozygous albino male (probability 2/3 = 66%) or a normal male (probability 1/3 = 33%). And you could have purchased either a heterozygous albino female (probability 2/3 = 66%) or a normal female (probability 1/3 = 33%).
Here are the possible pairing and progeny:
1) male = heterozygous albino x
1a) female = heterozygous albino --> 3/4 normal looking, 1/4 albino
1b) female = normal --> all normal looking
2) male = normal x
2a) female = heterozygous albino --> all normal looking
2b) female = normal --> all normal looking
As the probability of getting a heterozygous albino male is 2/3, and the probability of getting a heterozygous albino female is 2/3, the probability of getting a pair of heterozygous snakes is 2/3 times 2/3 = 4/9 = 44%. In other words, just over half the matings will produce all normal looking babies. And you can't tell whether the male is heterozygous albino and the female is normal, whether the female is heterozygous albino and the male is normal, or whether both male and female are normal.
If you start with one snake that is either albino or heterozygous albino, then you can fairly easily find out whether it's normal looking mate is normal or heterozygous albino.
Hope this helps.
Paul Hollander