I will use hypomelanism as an example but you could just as well plug in pastel, tiger, striped, piebald or jaguar. Hypomelanism is reduced black pigment. I'll assume this trait is controlled by two genes, which I'll call "a" and "b".
A = normal and is dominant
a = hypo and is recessive
B = normal and is dominant
b = hypo and is recessive
So here are all our possibilities:
Genotype Phenotype
___________________________________
AABB very dark (normal)
AABb or AaBB dark
AaBb or AAbb or aaBB medium
Aabb or aaBb light
aabb very light (hypomelanistic)
Now lets cross a heterozygous for hypomelanism with a homozygous for hypomelanism.
AaBb X aabb
First combine like terms: Aa x aa and Bb x bb. Then multiply each one out an get:
Aa Aa aa aa
Bb Bb bb bb
Then multiply each term to every other term and you come up with:
AaBb AaBb Aabb Aabb
AaBb AaBb Aabb Aabb
aaBb aaBb aabb aabb
aaBb aaBb aabb aabb
Next, combine like terms: 4AaBb 4Aabb 4aaBb 4aabb. These are the Genotypes.
And here is how they would appear, the phenotypes:
4 true hypomelanistic,
4 medium
8 light
Now just imagine what happens if the trait is controlled by 3 or more genes! That is why algebra is the prefered method to the pundit squares method. So the gene for tiger retic would just be ordinary recessive alleles controlled by two genes.
Paul Kemes

